Plot dynamics of an ODE

3 Ansichten (letzte 30 Tage)
UserCJ
UserCJ am 21 Sep. 2022
Kommentiert: Cris LaPierre am 22 Sep. 2022
I have an ODE and I need to plot with respect to and varying p. Following is the sample plot required.
I managed to draw one plot for and following is the sample code.
[xi,x] = meshgrid(0:0.001:1,0:0.002:1);
p =1
f2 = @(x,a,b) a*b*(x)./(b-2+x));
f1 = @(x,a,b) a*b*(1-x)./(2*b-x);
rs = @(x1,x2,a,b,p) x1.*f1(x,a,b) - p.*(1-x1).*f2(x,a,b);
figure
contour(x1,2,rs(x1,x2,1,2,1),[0 0]);
Next I added a loop for p as follows:
np = 10;
phi = linspace(0,1,np);
for p = 1:np
f2 = @(x,a,b) a*b*(x)./(b-2+x));
f1 = @(x,a,b) a*b*(1-x)./(2*b-x);
rs = @(x1,x2,a,b,p) x1.*f1(x,a,b) - p.*(1-x1).*f2(x,a,b);
R = rs(x1,x2,1,2, p(p));
contour(x1,x2,R);
hold on
end
hold off
But, instead of the required ourput of 10 plots in one graph, I get many plots (>10) in my output. Can someone please help me with this?
  1 Kommentar
Cris LaPierre
Cris LaPierre am 21 Sep. 2022
Bearbeitet: Cris LaPierre am 21 Sep. 2022
You have not copied your code correctly here, as both examples do not run.

Melden Sie sich an, um zu kommentieren.

Akzeptierte Antwort

Cris LaPierre
Cris LaPierre am 21 Sep. 2022
I'm assuming your goal is to plot a line for when the function rs is equal to zero for various values of p. You could do that using contour, but I don't think that is the best way. However, you could still use contour to get the (x,y) coordinates of the 0 contour line for each, and then plot those.
np = 10;
[x1,x2] = meshgrid(0:0.001:1,0:0.002:1);
for p = 1:np
f2 = @(x,a,b) a*b*(x)./(b-2+x);
f1 = @(x,a,b) a*b*(1-x)./(2*b-x);
rs = @(xi,x,a,b,p) xi.*f1(x,a,b) - p.*(1-xi).*f2(x,a,b);
R = rs(x1,x2,1,2, p);
figure(1)
M=contour(x1,x2,R,[0 0]);
figure(2)
plot(M(1,2:end),M(2,2:end),'DisplayName',"p="+p)
axis([0 1 0 1])
hold on
end
hold off
legend(Location="northwest")
  4 Kommentare
Cris LaPierre
Cris LaPierre am 22 Sep. 2022
I would keep the meshgrid approach. That will be faster than looping.
I'm not sure of a best way, but one way to do this without contour is to look for the min(abs(R)) in each row. This won't be the exact zero point, but will be close enough for the visualization.
np = 10;
X = 0.001:0.001:1;
Y = 0.002:0.002:1;
[x1,x2] = meshgrid(X,Y);
for p = 1:np
f2 = @(x,a,b) a*b*(x)./(b-2+x);
f1 = @(x,a,b) a*b*(1-x)./(2*b-x);
rs = @(xi,x,a,b,p) xi.*f1(x,a,b) - p.*(1-xi).*f2(x,a,b);
R = rs(x1,x2,1,2, p);
[xval,xind] = min(abs(R),[],2);
X_z0(:,p) = X(xind);
end
plot(X_z0,Y)
axis([0 1 0 1])
legend(Location="northwest")

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (0)

Kategorien

Mehr zu 2-D and 3-D Plots finden Sie in Help Center und File Exchange

Produkte


Version

R2022b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by