Incompatible Array Size/Mathematical Input Error
8 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
I was trying to get the "exact" function to work its rather long though, and I've typed it all out below in MATLAB.
For the exact equation I really don't know how I shoud even input the summation, since I've never worked with one like that before, so I suspect I've done that wrong or maybe I misinterperated the instuctions? But If anyone sees what I've done wrong I'd really appriciate it.

So far, I've typed everything in as follows:
clear;clc
x = 3.*[8 7 4];
V = [8 7 4];
R = [8 7 4];
Eo = V./(2.*R);
r = ((2.*R) + x)./(2.*R);
B = acosh(r);
n = 1:100;
S = x./(2.*R);
f = ((1./sinh(2.*n.*B)).*(1+r+(sinh(B).*((coth(2.*n.*B))))./(1-r-(sinh(B).*(coth(2.*n.*B)))).^2)+(cosh(2.*B))+r+(((2.*r)+1).*(sinh(B).*((coth(2.*n.*B)))))./(((cosh(2.*B))-r-(((2.*r)-1).*(sinh(B).*((coth(2.*n.*B)))))).^2));
E_max_simp = (Eo./4.*S).*(1+(2.*S)+sqrt((1+(2.*S)).^2)+8);
E_max_exac = Eo(1+((2.*r+1)/(2.*r-1)^2))+sinh(B).*syssum(f,n,1,inf);
0 Kommentare
Antworten (1)
Walter Roberson
am 20 Sep. 2022
x = 3.*[8 7 4];
V = [8 7 4];
R = [8 7 4];
Eo = V./(2.*R);
r = ((2.*R) + x)./(2.*R);
B = acosh(r);
syms m n integer
S = x./(2.*R);
E_max_simp = (Eo./4.*S).*(1+(2.*S)+sqrt((1+(2.*S)).^2)+8)
f = ((1./sinh(2.*n.*B)).*(1+r+(sinh(B).*((coth(2.*n.*B))))./(1-r-(sinh(B).*(coth(2.*n.*B)))).^2)+(cosh(2.*B))+r+(((2.*r)+1).*(sinh(B).*((coth(2.*n.*B)))))./(((cosh(2.*B))-r-(((2.*r)-1).*(sinh(B).*((coth(2.*n.*B)))))).^2));
E_max_exac = Eo .* (1+((2.*r+1)/(2.*r-1).^2))+sinh(B).*symsum(f,n,1,m);
E_max_exac_100 = vpa(subs(E_max_exac, m, 100))
Notice that your E_max_simp is constant. Notice that your Eo is a vector that has all entries work out to exactly 1/2, and notice that your E_max_simp does not involve n or any sum.. everything happens to cancel out leaving constants.
0 Kommentare
Siehe auch
Kategorien
Mehr zu Loops and Conditional Statements finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!