Hello I'm getting this warning "Variable 'x1' might be set by a nonscaler operator".
Ältere Kommentare anzeigen
This is a exercise to write a piece of code which would determine and plot the odd and even parts of a discontinuous time signal. It's not my code I just copied it from youtube. I would like to know why this code works just fine with continuous time signals and how can I rewrite the code to avoid this issue.
close; clear; clc;
n = -5:5;
A = 0.8;
x1 = A.^n;
x2 = A.^(-n);
if (x1 == x2)
disp('"The given signal is even!"')
elseif (x1 == (-x2))
disp('"the given signal is odd!"')
else
disp('"The given signal in nither odd nor even!"')
end

xe = ( x1 + x2 )/2;
xo = ( x1 - x2 )/2;
tiledlayout(2,2); nexttile;
stem(n,x1);
xlabel("n");
ylabel("x1(n)");
title("signal x(n)")
nexttile;
stem(n,x2);
xlabel("n");
ylabel("x2(n)");
title("signal x(-n)")
nexttile;
stem(n,xe);
xlabel("n");
ylabel("xe(n)");
title("Even Part of x(n)")
nexttile;
stem(n,xo);
xlabel("n");
ylabel("xo(n)");
title("Odd Part of x(n)")
Akzeptierte Antwort
Weitere Antworten (1)
KSSV
am 20 Sep. 2022
You case x1, x2 are vectors and you cannot use the condition like that.
You have to use like shown below.
n = -5:5;
A = 0.8;
x1 = A.^n;
x2 = A.^(-n);
idx = x1 == x2 ;
[x1(idx)' x2(idx)']
[x1(~idx)' x2(~idx)']
Kategorien
Mehr zu Mathematics finden Sie in Hilfe-Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!

