Drawing using if function
2 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
Lina Alhelo
am 14 Sep. 2022
Kommentiert: Jan
am 15 Sep. 2022
Hi all;
I would like to generate drawing (graph) for Y and X when ever N value is Yes . Can you help me in writting the code
3 Kommentare
Jan
am 15 Sep. 2022
@Lina Alhelo: For Matlab X, Y and N are arrays of a certain type. It does not matter, if they represent vehicles, US$ or intergalactic spaceships. But it does matter, if they are ouble vectors, cell strings, string arrays, etc. and what values they have. Therefore a short explicit example of input data is more useful than explaining the physical meaning of the variables.
Akzeptierte Antwort
Walter Roberson
am 14 Sep. 2022
places = find(strcmp(N, 'Yes'));
now plot() using 'MarkerIndices', places
0 Kommentare
Weitere Antworten (1)
vamshi sai yele
am 14 Sep. 2022
Hi Lina,
I understood that, based on the 'N' condition, you want to communicate whether accident took place or not. I have tried from my end and below is the solution for the same. I made the below code from my understanding towards this question.
In the code depending upon the 'N' value initially, the "if" condition displays a graph or a message. In this test case, I have tried to display the "cos" graph when the condition is satisfied. In your project kindly set up the required graph. Also note that, saying "Yes" is same as "True" and logical value "1" [Yes==True==1].
N = 1
if N == 1
Accident()
else
display("No accident, everyone are safe")
end
function Accident()
f=5;
time=2;
Ts=1/100;
t=Ts:Ts:time;
x=(cos(2*pi*f*t));
plot(t,x)
end
For detailed information and for other case implimentations on "if" condition, refer to this link
Hope I have addressed your question and you find it helpful!
0 Kommentare
Siehe auch
Kategorien
Mehr zu Directed Graphs finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!