Create a graph with square function of period different to 2π
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Ricard Escriva
am 6 Sep. 2022
Kommentiert: Ricard Escriva
am 6 Sep. 2022
Hello,
I am trying to create a function like attached.
I created a square wave but apparently the period is fixed and equal to 2π. My approach has been to create three different functions, one for charge, one for idle and one for discharging.
Thank you very much, I attach the code I have so far:
t = linspace(0,23,24);
P1 = 100*square(t,96);
P2 = 0*square(t,4);
P3 = 220*square(t,4);
plot(t,P1)
hold on
plot(t,P2)
plot(t,P3)
xlim([0,24])
xlabel('time [h]')
ylabel('Power [MW]')
grid on
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Akzeptierte Antwort
Sam Chak
am 6 Sep. 2022
Bearbeitet: Sam Chak
am 6 Sep. 2022
Maybe like this?
t = linspace(0, 24, 2401);
duty1 = 100*10/24; % 10 hours in percentage
delay1 = 3; % 3 hours
P1 = (100/2)*square((t - delay1)*2*pi/24, duty1) + 100/2;
P2 = zeros(length(t));
duty3 = 100*4/24; % 4 hours in percentage
delay3 = 18; % 18 hours
P3 = (220/2)*square((t - delay3)*2*pi/24, duty3) + 220/2;
plot(t, P1, 'k-', 'linewidth', 1.5), hold on
plot(t, P3, 'g-', 'linewidth', 1.5), hold on
plot(t, P2, 'b--', 'linewidth', 1.5)
xlim([0, 24])
xticks([0 6 12 18 24])
ylim([-50 250])
xlabel('time [h]')
ylabel('Power [MW]')
grid on
legend('Charging', 'Discharging', 'Idle', 'location', 'northwest')
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