Unclear array operation in matlab

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Himanshu
Himanshu on 1 Sep 2022
Edited: Himanshu on 1 Sep 2022
Dear all, I have created a 5 * 3 array, named as 'conn' and another array as lm which is 1*2 as underneath:
conn= [1 5 6; 2 5 7; 3 4 5 ; 4 5 7; 5 6 8];
lm = [4 ,3];
conn(lm)
while running the code, it gives me the following output.
ans =
4 3
this operation with "conn(lm)" is totally unclear to me when I operate on 5*3 array. I will be grateful if anyone please help me to understand this code.

Answers (2)

Chunru
Chunru on 1 Sep 2022
conn= [1 5 6; 2 5 7; 3 4 5 ; 4 5 7; 5 6 8]
conn = 5×3
1 5 6 2 5 7 3 4 5 4 5 7 5 6 8
lm = [4 ,3];
% The following use lm as "linear" index to reference to conn
% The "linear" index count column by column
% so the 4th element of conn is (4,1)
conn(lm)
ans = 1×2
4 3
conn(10) % (5,2)th element of conn
ans = 6
  1 Comment
Himanshu
Himanshu on 1 Sep 2022
Edited: Himanshu on 1 Sep 2022
Thank you very much. This was helpful and precise.

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weikang zhao
weikang zhao on 1 Sep 2022
Hello, this is matlab's unique indexing mechanism. For a 5*3 matrix, you can use 1-15 to index all elements.
Matlab uses column-major order, so your code is the same as the result below.
coon=[1 2 3 4 5 5 5 4 5 6 6 7 5 7 8];
lm=[4 3];
The output results are organized as follows
conn(lm)=[coon(4) coon(3)]=[4 3]
Incorrect use of '=' operator. Assign a value to a variable using '=' and compare values for equality using '=='.

Error in connector.internal.fevalMatlab

Error in connector.internal.fevalJSON

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