Plot time series data

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Nurfaiz Fathurrahman
Nurfaiz Fathurrahman am 30 Aug. 2022
Beantwortet: Lei Hou am 31 Aug. 2022
first, sorry for my english
i have the data below
2022-08-27T00:00:00.019538 16065
2022-08-27T00:00:00.044538 16871
2022-08-27T00:00:00.069538 16800
2022-08-27T00:00:00.094538 16574
2022-08-27T00:00:00.119538 17022
2022-08-27T00:00:00.144538 17021
2022-08-27T00:00:00.169538 16746
2022-08-27T00:00:00.194538 16948
first column is date and time, second column is data
I want to make a timeseries plot, I've tried with
ts = timeseries(data, time)
and then i get error
Error using datenum (line 189)
DATENUM failed.
Error in timeseries/init (line 318)
[~, data, quality, I] = timeseries.utsorttime(datenum(time),...
Error in timeseries (line 343)
this = init(this,varargin{:});
Caused by:
Error using datevec (line 217)
Failed to lookup month of year.
how to make timeseries from data above? thank you
  2 Kommentare
Walter Roberson
Walter Roberson am 30 Aug. 2022
Are you sure you need timeseries()? Would it be plausible to instead use the newer timetable() ?
Nurfaiz Fathurrahman
Nurfaiz Fathurrahman am 30 Aug. 2022
I'm not sure, I need to plot the above data to get a graph like this
is it possible to use timetable()? Or is there another method besides these two methods?

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Antworten (2)

Star Strider
Star Strider am 30 Aug. 2022
Bearbeitet: Star Strider am 30 Aug. 2022
Try something like this —
C = {'2022-08-27T00:00:00.019538' 16065
'2022-08-27T00:00:00.044538' 16871
'2022-08-27T00:00:00.069538' 16800
'2022-08-27T00:00:00.094538' 16574
'2022-08-27T00:00:00.119538' 17022
'2022-08-27T00:00:00.144538' 17021
'2022-08-27T00:00:00.169538' 16746
'2022-08-27T00:00:00.194538' 16948};
DT = datetime(C(:,1), 'InputFormat','yyyy-MM-dd''T''HH:mm:ss.SSSSSS', 'Format','yyyy-MM-dd HH:mm:ss.SSSSSS')
DT = 8×1 datetime array
2022-08-27 00:00:00.019538 2022-08-27 00:00:00.044538 2022-08-27 00:00:00.069538 2022-08-27 00:00:00.094538 2022-08-27 00:00:00.119538 2022-08-27 00:00:00.144538 2022-08-27 00:00:00.169538 2022-08-27 00:00:00.194538
T1 = table(DT, cell2mat(C(:,2)))
T1 = 8×2 table
DT Var2 __________________________ _____ 2022-08-27 00:00:00.019538 16065 2022-08-27 00:00:00.044538 16871 2022-08-27 00:00:00.069538 16800 2022-08-27 00:00:00.094538 16574 2022-08-27 00:00:00.119538 17022 2022-08-27 00:00:00.144538 17021 2022-08-27 00:00:00.169538 16746 2022-08-27 00:00:00.194538 16948
figure
plot(T1{:,1}, T1{:,2})
grid
xtickformat('mm:ss.SSS')
xtickangle(30)
If your data are in a file, use readtable and then do the appropriate datetime conversion as I outlined here.
EDIT — Corrected typographical errors, added xtickformat and xtickangle calls. .
.

Lei Hou
Lei Hou am 31 Aug. 2022
The function 'stackedplot' is designed for plotting time series.
>> C = {'2022-08-27T00:00:00.019538' 16065
'2022-08-27T00:00:00.044538' 16871
'2022-08-27T00:00:00.069538' 16800
'2022-08-27T00:00:00.094538' 16574
'2022-08-27T00:00:00.119538' 17022
'2022-08-27T00:00:00.144538' 17021
'2022-08-27T00:00:00.169538' 16746
'2022-08-27T00:00:00.194538' 16948};
>> DT = datetime(C(:,1), 'InputFormat','yyyy-MM-dd''T''HH:mm:ss.SSSSSS', 'Format','yyyy-MM-dd HH:mm:ss.SSSSSS');
>> numericValue = cell2mat(C(:,2));
>> tt = timetable(numericValue,'RowTimes', DT)
tt =
8×1 timetable
Time numericValue
__________________________ ____________
2022-08-27 00:00:00.019538 16065
2022-08-27 00:00:00.044538 16871
2022-08-27 00:00:00.069538 16800
2022-08-27 00:00:00.094538 16574
2022-08-27 00:00:00.119538 17022
2022-08-27 00:00:00.144538 17021
2022-08-27 00:00:00.169538 16746
2022-08-27 00:00:00.194538 16948
>> stackedplot(tt)

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