How can I create a matrix out of a matrix?
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Hello,
% I have a matrix as below:
A=[0 0 0;5 2 4;0 0 0;4 1 8;9 5 6;0 0 0]
% My 2.,4. and 5. rows are different than '0'. As a result I wanna have a matrix as below including the number of rows different than '0':
B=[2 5 2 4;4 4 1 8;5 9 5 6];
However, I have a bigger matrix in my real problem. It is just an example
Thx
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Antworten (3)
Mischa Kim
am 17 Feb. 2015
Rengin, you could use, e.g.
B = [(1:size(A,1))' A];
B(~any(B(:,2:end),2),:) = []
12 Kommentare
Mischa Kim
am 19 Feb. 2015
Bearbeitet: Mischa Kim
am 19 Feb. 2015
After computing Xs add
B = [(1:size(Xs,1))' Xs];
B(~any(B(:,2:end),2),:) = []
to get
B =
1.0e+02 *
0.190000000000000 1.387778103306779 0.343814253001248
0.250000000000000 0.208481799046993 0.176385990188109
1.170000000000000 0.458209269814333 3.910781553669295
1.280000000000000 0.483323512292465 0.264376184324426
1.820000000000000 0.684481966455650 0.795152138548950
3.240000000000000 0.846839613465022 1.292539618758099
3.610000000000000 0.568404629169297 0.577528050340383
4.340000000000000 0.190023379731620 0.466716273193995
4.770000000000000 1.018698679681144 2.434206303256232
The first column contains the row numbers: 19, 25, 117, etc.
To your second question: the variable iter is set to 5 when you enter the for-loop, most likely because it is set to that value in one of the other scripts. Simply use a different (new) variable name, e.g. my_iter, and it'll work.
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