![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/1109005/image.jpeg)
what dose z represent in this graph?
1 Ansicht (letzte 30 Tage)
Ältere Kommentare anzeigen
I am studying these graphs , and I really confused in some points here.
1- when we take arbitrary point in this figure for example as we can see in the first figure (x= -0.465, y=0.325, z=0.0084), we see that z>0 (greter than 0)
but when we calculate (cos(angle(-0.465+0.325i))) , we got it = -.8196 <0 (les than zero )
)
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/1108975/image.png)
it is clear from this figure z does not equal the value of the function (cos(angle(-0.465+0.325i))), and
if z indicate to the sign of this function , why we got z>0 whereas the value of this function <o?
My questions are,
Is z in this figure indiacet to the value of (cos(angle(-0.465+0.325i))) or only tells us where (cos(angle(-0.465+0.325i))) positinve and negative? and why we find this contrast?
I will appreciate any help.
5 Kommentare
Walter Roberson
am 26 Aug. 2022
My answer was in preparation when you posted yours. We happened to close to the same thing.
Antworten (0)
Siehe auch
Kategorien
Mehr zu Image Processing Toolbox finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!