Find complete rows that meet a condition

I would like to find a way to select rows from an array that meet a certain condition. In the case of single elements this is very simple, but I don't know how to do it for full rows/columns. For example, if you have the array

A = [1 2;
     3 1;
     0 6;
     2 0]

and the variable

x1 = [3 1]

I would want to know the rows in A that are not equal to x1, so A(1,:), A(3,:) and A(4,:). Of course it's easy to just make a for loop, but I wonder if there's a simpler/more elegent way.

Answer 1

[Cris LaPierre]

You could use two conditions - one for the first column and another for the 2nd column - to find the rows that meet your criteria.

A = [1 2;
     3 1;
     0 6;
     2 0];
x1 = [3 1];

% row numbers
rows = find(A(:,1)~=x1(1) & A(:,2)~=x1(2))

rows = 3×1

1 3 4

% row values
A(rows,:)

ans = 3×2

1 2 0 6 2 0

[Piet Bouwens]

Ah that makes sense, thanks a lot!