Plotting an integral function
5 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
I am trying to plot the followng equation. I am solving for stress.
My professor has told us that h' will be negative in the first and positive in the second. I used the following code, but my plot just shows a straight line. I think I should end up with a curve.
L=1.5;
h=.2;
s=.75*L;
tbar=1;
y=0;
for xbar=-1.5:.1:1.5
if xbar>-L & s>xbar
hprime=0.75;
else
hprime=-0.75;
end
fun= @(xbar) ((2*hprime)*((xbar-tbar)^3))/(((xbar-tbar)^2+y^2)^2);
Sxx1=integral(fun,-L,-s, 'ArrayValued',1);
Sxx2=integral(fun,s,L, 'ArrayValued',1);
Sxx=(((L-s)/h)*(Sxx1+Sxx2));
figure(1)
plot(Sxx,xbar,'.')
hold on
grid
title('Sxx vs xbar')
end
0 Kommentare
Akzeptierte Antwort
Torsten
am 3 Aug. 2022
L=1.5;
h=.2;
s=.75*L;
tbar=1;
y=0;
icount = 0;
for xbar=-1.5:.1:1.5
icount = icount + 1;
if xbar>-L & s>xbar
hprime=0.75;
else
hprime=-0.75;
end
fun= @(tbar) ((2*hprime)*((xbar-tbar)^3))/(((xbar-tbar)^2+y^2)^2);
Sxx1=integral(fun,-L,-s, 'ArrayValued',1);
Sxx2=integral(fun,s,L, 'ArrayValued',1);
Sxx(icount)=(((L-s)/h)*(Sxx1+Sxx2));
%figure(1)
%plot(Sxx,xbar,'.')
%hold on
%grid
%title('Sxx vs xbar')
end
plot(-1.5:0.1:1.5,Sxx)
0 Kommentare
Weitere Antworten (0)
Siehe auch
Kategorien
Mehr zu Animation finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!