how to fix this error 'interp2'

1 Ansicht (letzte 30 Tage)
BA am 28 Jul. 2022
Bearbeitet: Matt J am 28 Jul. 2022
%identify axes
[x y] = ginput(2);
% preallocate matrices
cog = zeros(size(matrix,3),1);
% loop start
for i = 1:size(matrix,3)
I = matrix(:,:,i);
n = ceil(norm([diff(x), diff(y)]));
test = interp2(I, linspace(x(1), x(2),n), linspace(y(1), y(2),n));
cog(i) = sum((1:length(test)).*test')/sum(test);
% loop end
scog = (cog - min(cog)) / (max(cog) - min(cog));

Antworten (1)

Matt J
Matt J am 28 Jul. 2022
Because your first argument to interp2 is a matrix while the second is a scalar.
  6 Kommentare
Steven Lord
Steven Lord am 28 Jul. 2022
From these questions: 1, 2 it sounds like the poster is using Octave rather than MATLAB. If that's the case, that would explain the difference in the appearance of the error message.

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