Unrecognized function or variable 'e1'.
s1=x3.^2+x1*x3+x1.^2;
s2=x1.^4+x1.^3*x3+x1.^2*x3.^2 +x1.^2*x3.^2+x1*x3.^3 + x3.^4;
%s1=x2.^2+x1*x2+x1.^2;
%s2=x1.^4+x1.^3*x2+x1.^2*x2.^2 +x1.^2*x2.^3 + x2.^4;
%u1 = -e1-e2;
%u2 = beta*e1*k1 +gamma*e1*k2+omegaf*e1-ff2*cos(W2*t)+ff1*cos(W1*t);
u1 = -e2-e1;
u2 = beta*e1*s1 + gamma*e1*s2+omegaf*e1-ff2*cos(W2*t)+ff1*cos(W1*t);
%sys-I
dx1=x2;
dx2=-alpha*x2-omegaf*x1-beta*x1.^3- gamma*x1.^5+ff1*cos(W1*t);
%sys -II
dx3=x4+u1;
dx4=-alpha*x4-omegaf*x3-beta*x3.^3- gamma*x3.^5+ff2*cos(W2*t)+u2;
de1=dx3-dx1;
de2=dx4-dx2;
e1 = x3-x1;
e2= x4-x2;
de1=e2+u1;
de2=-alpha*e2-omegaf*e1-beta*e1*s1- gamma*e1*s2+ff2*cos(W2*t)-ff1*cos(W1*t)+u2;
dy = [dx1; dx2; dx3; dx4];
end

2 Kommentare

prajith samraj
prajith samraj am 18 Jul. 2022
i need e1 and e2 graph. what can i do?
e1 = y(:,3)-y(:,1);
e2= y(:,4)-y(:,2);

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 Akzeptierte Antwort

Sam Chak
Sam Chak am 19 Jul. 2022

2 Stimmen

Try manipulating the parameters to get different results.
% Solver
tspan = [0 20];
x10 = 0.11;
x20 = 0.1;
x30 = 0.21;
x40 = 0.2;
y0 = [x10; x20; x30; x40];
[t, y] = ode45(@(t, y) f(t, y), tspan, y0);
% Plots
e1 = y(:, 3) - y(:, 1);
e2 = y(:, 4) - y(:, 2);
subplot(2,1,1)
plot(t, e1), grid on, xlabel('t'), ylabel('e_{1}')
subplot(2,1,2)
plot(t, e2), grid on, xlabel('t'), ylabel('e_{2}')
function dy = f(t, y)
% parameters
alpha = 0.5;
omegaf = -1;
beta = 0.8790;
gamma = 0.3000;
W1 = 1.4450;
ff1 = 0.5381;
W2 = 1.4450;
ff2 = 0.5381;
% assignment
x1 = y(1);
x2 = y(2);
x3 = y(3);
x4 = y(4);
e1 = x3 - x1;
e2 = x4 - x2;
s1 = x3^2 + x1*x3 + x1^2;
s2 = x1^4 + (x1^3)*x3 + (x1^2)*(x3^2) + (x1^2)*(x3^2) + x1*(x3^3) + x3^4;
u1 = - e2 - e1;
u2 = beta*e1*s1 + gamma*e1*s2 + omegaf*e1 - ff2*cos(W2*t) + ff1*cos(W1*t);
% sys I
dx1 = x2;
dx2 = - alpha*x2 - omegaf*x1 - beta*x1^3 - gamma*x1^5 + ff1*cos(W1*t);
% sys II
dx3 = x4 + u1;
dx4 = - alpha*x4 - omegaf*x3 - beta*x3^3 - gamma*x3^5 + ff2*cos(W2*t) + u2;
de1 = dx3 - dx1;
de2 = dx4 - dx2;
dy = [dx1; dx2; dx3; dx4];
end

2 Kommentare

prajith samraj
prajith samraj am 19 Jul. 2022
i need the value of e1dot and e2 dot graph
Sam Chak
Sam Chak am 19 Jul. 2022
@prajith samraj, I'm a little confused now. In your comment, you clearly mentioned that you need e1 and e2 graph. Perhaps, you unintentionally confused yourself with e1dot and e2dot?
Please edit the title of your question for clarity...

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