Create an array of numbers

hey guys, thanks in advance

I have this matrix attached , distance_matrix. Basically is the position of a plane along a linear direction.

I have this code that finds the minimum value, which means distance to a target according to the specific position of the plane.

What I want to do , is assume that R0 is the origin of the plane movement( column 184). But we can see that plane has more positions, column 185,186,etc... I want to create an array of positions, where R0 is the center( perhaps x=0), and as the example in the matrix 185(x=1), 186(x=2),... 190(x=6). The inf numbers in the matrix doesn´t matter, but I still need that positions occupied.

But I also want that the code could assume that if R0= 190, then columns 184(x=-6), 185(x=-5),... 191(x=1),...

R0=min(distance_matrix(distance_matrix ~= 0));

Answer 1

[dpb]

[R0,ixR0]=min(distance_matrix(distance_matrix ~= 0));
x=(1:numel(distance_matrix))-ixR0;

[Miguel Albuquerque]

I have done this code:

I think its correct, your code says ixR0 is 1, when it is 184

[rows,columns]=size(distance_matrix);
distance_matrix(distance_matrix==0) = NaN ;
[val,idx] = min(distance_matrix);
for col = 1 : columns
    thisColumn = distance_matrix(:, col);
    idx2=col-idx;
    tshift(:,col)=(idx2.^2)./ (val.*c);
end

[dpb]

Not what I get with the data file you attached --

>> [R0,idx]=min(distance_matrix(distance_matrix ~= 0))
R0 =
   84.9718
idx =
   184
>> 

Looks right to me...dunno how you got something different -- the 1 value would indicate you somehow applied to a subset of the data from that point on.

Of course, you get same result from...

>> [R0,idx]=min(distance_matrix)
R0 =
   84.9718
idx =
   184
>>