I have a 3-D array where the first column is month, the second column is city, and the third column is a vector of temperature of the city in that month. I have previosuly sorted the temperature in the descending order. Then I now want to create a 3-D array where the first column is month, the second column is city, and the third columnis the n-th highest temperature of the month of the city. Please advise how to proceed.

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Steven Lord
Steven Lord am 15 Jul. 2022

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I have a 3-D array where the first column is month, the second column is city, and the third column is a vector of temperature of the city in that month.
So the array has size [N 3] for some value of N? That's not a 3-dimensional array. That's a matrix with three columns.
Then I now want to create a 3-D array where the first column is month, the second column is city, and the third columnis the n-th highest temperature of the month of the city.
I'm going to assume you mean that you want another matrix with three columns. As you've described it, you should use the groupsummary function. You can use the "Multiple Grouping Variables" or "Multiple Grouping Vectors for Vector Input" examples on that documentation page as a model.

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alpedhuez
alpedhuez am 15 Jul. 2022
The array has
12 (months) * 10 (# of cities) * (30 records of temperature for each day of a month).
I want to create an array of
12*10*1 (highst temperture of the month of the city)
Torsten
Torsten am 15 Jul. 2022
Bearbeitet: Torsten am 15 Jul. 2022
A = sort(A,3,'descent');
A = squeeze(A(:,:,1))
gives a 12x10 matrix with the highest temperatures in month i in city j.
alpedhuez
alpedhuez am 15 Jul. 2022
Thank you. Is there any simple way to extract the second highest, third highest,...?
k-th highest:
A = squeeze(A(:,:,k))

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