unable to get desired results

Please find the below code.

User = zeros(1,10);

for i = 1:10

probability_of_transmission = rand(1);

if probability_of_transmission > p

j = 5;

User(i) = 1;

else

User(i) = 0;

end

end

I just want the output to be somewhat like: User = [ 0 0 0 1 1 1 1 1 0 0 ]. How can i put one more if argument in the for loop so that at the end i will get consecutive ones insetead of ones at random index.

[Torsten]

What is the task behind the creation of the vector "User" ?

[Prashant Bhagat]

It is for random transmission for User. I am trying it for one user intially then i will try to do it for large number of users

[Abderrahim. B]

and what does that j doing there in your loop ? With using rand to compute probability_of_transmission you can't get the User vector you want.

[Prashant Bhagat]

j is the number of time slots required for transmission of one packet. Then what i have to do to get the desired output

Answer 1

[Voss]

Maybe this?

User = zeros(1,10);
p = 0.785;

for i = 1:10
    probability_of_transmission = rand(1);
    if probability_of_transmission > p
        j = 5;
        User(i+(0:j-1)) = 1;
    end
end

User

User = 1×10

0 0 0 1 1 1 1 1 0 0

Note that the sequences of 5 ones may overlap each other and may also extend User to beyond 10 elements; it's not clear whether those aspects would be bugs or features for what you want to do.

[Prashant Bhagat]

Thanks

[Voss]

You're welcome!