unable to get desired results
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Prashant Bhagat
am 13 Jul. 2022
Kommentiert: Voss
am 13 Jul. 2022
Please find the below code.
User = zeros(1,10);
for i = 1:10
probability_of_transmission = rand(1);
if probability_of_transmission > p
j = 5;
User(i) = 1;
else
User(i) = 0;
end
end
I just want the output to be somewhat like: User = [ 0 0 0 1 1 1 1 1 0 0 ]. How can i put one more if argument in the for loop so that at the end i will get consecutive ones insetead of ones at random index.
4 Kommentare
Abderrahim. B
am 13 Jul. 2022
and what does that j doing there in your loop ? With using rand to compute probability_of_transmission you can't get the User vector you want.
Akzeptierte Antwort
Voss
am 13 Jul. 2022
Maybe this?
User = zeros(1,10);
p = 0.785;
for i = 1:10
probability_of_transmission = rand(1);
if probability_of_transmission > p
j = 5;
User(i+(0:j-1)) = 1;
end
end
User
Note that the sequences of 5 ones may overlap each other and may also extend User to beyond 10 elements; it's not clear whether those aspects would be bugs or features for what you want to do.
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