I couldn't understand why this program is not working, is my all variable algorithm is correct?

1 Ansicht (letzte 30 Tage)
clc
ti = 0;
tf = 10E-4;
tspan=[ti tf];
y0=[9;9;1;1;0].*10E-2;
I =0:0.1 :10 ;
Vf = zeros(length(I),1) ;
for i = 1:length(I)
[T,Y]= ode45(@(t,y) rate_eq(y,I(i)),tspan,y0);
Vf(i) = (2.*(((mean(Y(:,1).*Y(:,2).*cos(Y(:,5)))).^2 + (mean(Y(:,1).*Y(:,2).*sin(Y(:,5)))).^2).^0.5))/(mean(Y(:,1).^2)+mean(Y(:,2).^2));
end
disp(Vf)
NaN 0.3065 0.3449 0.3443 0.3617 0.3454 0.3619 0.3656 0.3589 0.3651 0.3622 0.3700 0.3750 0.3650 0.3792 0.3500 0.3687 0.3655 0.3635 0.3725 0.3723 0.3652 0.3573 0.3717 0.3687 0.3656 0.3690 0.3614 0.3664 0.3588 0.3699 0.3821 0.3566 0.3635 0.3592 0.3654 0.3608 0.3605 0.3619 0.3630 0.3488 0.3517 0.3569 0.3543 0.3494 0.3595 0.3527 0.3370 0.3590 0.3579 0.3559 0.3545 0.3431 0.3577 0.3573 0.3474 0.3441 0.3554 0.3269 0.3347 0.3372 0.3471 0.3389 0.3368 0.3298 0.3292 0.3219 0.3263 0.3443 0.3386 0.3260 0.3428 0.3151 0.3296 0.3156 0.3189 0.3200 0.3148 0.3134 0.3150 0.3299 0.3187 0.3071 0.3029 0.3232 0.3056 0.2895 0.2976 0.3067 0.2846 0.3003 0.2848 0.2940 0.2972 0.2976 0.3055 0.3036 0.2962 0.2932 0.2946 0.3023
function dy = rate_eq(y,I)
dy = zeros(5,1);
o = 2E5; %detuning frequency
tc = 30E-9; %photon cavity lifetime
tf = 230E-6; %fluorescence lifetime
a1 = 0.1; %roundtrip loass
a2 = 0.1;
P1 = 0.2; %pumpstrength
P2 = 0.2;
kc = 3E-3; %critical coupling strength
s = 0.17;
k = s.*kc;
%amplitude equation
dy(1) = ((y(3) - a1) * y(1) + k * y(2) * cos(y(5))) ./ tc;
dy(2) = ((y(4) - a2) * y(2) + k * y(1) * cos(y(5))) ./ tc;
%gain medium strength
dy(3) = (P1 - y(3) * (((abs(y(1)))^2 .*I) + 1)) / tf;
dy(4) = (P2 - y(4) * (((abs(y(2)))^2 .*I) + 1)) / tf;
%phase differential equation
dy(5) = o - (k / tc) * (((y(1) ./ y(2)) + (y(2) ./ y(1))) * sin(y(5)));
end
  3 Kommentare

Melden Sie sich an, um zu kommentieren.

Akzeptierte Antwort

KSSV
KSSV am 12 Jul. 2022
You need to interchange the variables to the function rate_eq. Try this:
ti = 0;
tf = 10E-4;
tspan=[ti tf];
y0=[9;9;1;1;0].*10E-2;
[T,Y]= ode45(@(t,y) rate_eq(t,y),tspan,y0);
I =0:0.1 :10 ;
Vf = zeros(length(I),1) ;
for i = 1:length(I)
[T,Y]= ode45(@(t,y) rate_eq(I(i),y),tspan,y0);
Vf(i) = (2.*(((mean(Y(:,1).*Y(:,2).*cos(Y(:,5)))).^2 + (mean(Y(:,1).*Y(:,2).*sin(Y(:,5)))).^2).^0.5))/(mean(Y(:,1).^2)+mean(Y(:,2).^2));
end
disp(I)
function dy = rate_eq(I,y)
dy = zeros(5,1);
o = 2E5; %detuning frequency
tc = 30E-9; %photon cavity lifetime
tf = 230E-6; %fluorescence lifetime
a1 = 0.1; %roundtrip loass
a2 = 0.1;
P1 = 0.2; %pumpstrength
P2 = 0.2;
kc = 3E-3; %critical coupling strength
s = 0.17;
k = s.*kc;
%amplitude equation
dy(1) = ((y(3) - a1) * y(1) + k * y(2) * cos(y(5))) ./ tc;
dy(2) = ((y(4) - a2) * y(2) + k * y(1) * cos(y(5))) ./ tc;
%gain medium strength
dy(3) = (P1 - y(3) * (((abs(y(1)))^2 .*I) + 1)) / tf;
dy(4) = (P2 - y(4) * (((abs(y(2)))^2 .*I) + 1)) / tf;
%phase differential equation
dy(5) = o - (k / tc) * (((y(1) ./ y(2)) + (y(2) ./ y(1))) * sin(y(5)));
end
  2 Kommentare
SAHIL SAHOO
SAHIL SAHOO am 12 Jul. 2022
would you explain me, if I change my dy =zeros(5,1) to dy = zeros(4,1) still it's working, why so?
I have 5 coupled differential equation this shouldn't happen right?
KSSV
KSSV am 12 Jul. 2022
Though you define,dy = zeros(4,1)...you are defining
dy(5) = o - (k / tc) * (((y(1) ./ y(2)) + (y(2) ./ y(1))) * sin(y(5)));
so your dy is 5x1.

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (0)

Kategorien

Mehr zu Programming finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by