How to apply moving harmonic average on an array?
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Nisar Ahmed
am 3 Jul. 2022
Bearbeitet: dpb
am 4 Jul. 2022
Hi,
I have attached the data Kd_i = (115*1), I want to keep first and last values as it is in the data (or also shown in the figure below) and in the row want compute the harmonic average of first and second values (red square), in the 3rd row I want to compute the harmonic average of second and thrid values (green square) asn so on...
I mean first and last values remain same (just to have final array/vector of equal length), and then from second row it moves the by computing the harmonic mean of first and second row, until second last row. Can someone help me to write it code?
Thanks
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/1053925/image.png)
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Abhishek Tiwari
am 3 Jul. 2022
Hi,
A 'For' loop and harmmean() may do the same thing, as shown.
n = numel(Kd_i);
harmonicMean = Kd_i;
for idx = 2:n-1
harmonicMean(idx) = harmmean(Kd_i(idx-1 : idx, 1));
end
3 Kommentare
Abhishek Tiwari
am 4 Jul. 2022
Yeah, harmonicMean has first and last values from Kd_i, and the remaining are the harmonic means of two rows (prev. and current).
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Star Strider
am 3 Jul. 2022
If you want to calculate it as described in the harmmean More About section, perhaps something like this would work —
movhm = @(x) 2./movsum(1./x,2);
v = 1:5
movhm(v)
would work.
.
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dpb
am 3 Jul. 2022
Bearbeitet: dpb
am 4 Jul. 2022
Simplest is probably just brute-force --
HM=[Kd_1(1) arrayfun(@(i)harmmean(Kd_1(i:i+1)),1:numel(Kd_1)-1) Kd_1(end)].';
2 Kommentare
dpb
am 4 Jul. 2022
Yeah, I made a local array of K=Kd_1(1:15) so wasn't too much to look at in command window...then didn't fix -- and arrayfun returns row vector didn't transpose...
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