Using for loop in matlab

Hi everyone, I am assigning these values not in a very efficient way, can you suggest me how can i do it more efficiently? Thank you so much.

%Zone 1
    absx(1,81)=0;
    absy(1,81)=0;
    absx(1,82)=0;
    absy(1,82)=0;
    absx(1,83)=450;
    absy(1,83)=0;
    absx(1,84)=450;
    absy(1,84)=0;
    absx(1,85)=450;
    absy(1,85)=450;
    absx(1,86)=450;
    absy(1,86)=450;
    absx(1,87)=0;
    absy(1,87)=450;
    absx(1,88)=0;
    absy(1,88)=450;

%Zone 2

      absx(1,89)=0;
      absy(1,89)=900;
      absx(1,90)=0;
      absy(1,90)=900;
      absx(1,91)=450;
      absy(1,91)=900;
      absx(1,92)=450;
      absy(1,92)=900;
      absx(1,93)=450;
      absy(1,93)=1350;
      absx(1,94)=450;
      absy(1,94)=1350;
      absx(1,95)=0;
      absy(1,95)=1350;
      absx(1,96)=0;
      absy(1,96)=1350;

%Zone 3

    absx(1,97)=900;
    absy(1,97)=0;
    absx(1,98)=900;
    absy(1,98)=0;
    absx(1,99)=900+450;
    absy(1,99)=0;
    absx(1,100)=900+450;
    absy(1,100)=0;
    absx(1,101)=900+450;
    absy(1,101)=450;
    absx(1,102)=900+450;
    absy(1,102)=450;
    absx(1,103)=900;
    absy(1,103)=450;
    absx(1,104)=900;
    absy(1,104)=450;

%Zone 4

    absx(1,105)=900;
    absy(1,105)=900;
    absx(1,106)=900;
    absy(1,106)=900;
    absx(1,107)=900+450;
    absy(1,107)=900;
    absx(1,108)=900+450;
    absy(1,108)=900;
    absx(1,109)=900+450;
    absy(1,109)=900+450;
    absx(1,110)=900+450;
    absy(1,110)=900+450;
    absx(1,111)=900;
    absy(1,111)=1350;
    absx(1,112)=900;
    absy(1,112)=1350;

[Andreas Goser]

Why do you think it is not efficient?

[Aftab Ahmed Khan]

Well, its like 60 lines of code for doing a simple task. I am sure it can be done more efficently in a for loop.

Answer 1

[Matt J]

You would do things like the following

    absx=zeros(1,112);
    absy=zeros(1,112);

    %Zone 1
    absx(83:86)=450;
    absy(85:88)=450

and similarly for the other Zones.