minimun value in a column matrix with its index
2 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
kurdistan mohsin
am 10 Jun. 2022
Kommentiert: Voss
am 10 Jun. 2022
hi, I write the bellow code to find the minimum value in a column vector but it should not consider zero as a minimum , but how to find the exact indexing of the minimum value?
in the example the row index of minimum value exept zero should be 2 , why it give me 1?
can anybody correct it for me so the row_idx = 2 !
A=[0; 5 ;6 ;9 ;55]
[min_value,row_idx]=min(A(A~=0))
0 Kommentare
Akzeptierte Antwort
Dyuman Joshi
am 10 Jun. 2022
Bearbeitet: Dyuman Joshi
am 10 Jun. 2022
A=[0; 5 ;6 ;9 ;55]
A(A~=0) %when you do this, your vector changes
Method 1
minvalue=min(A(A~=0))
rowidx=find(A==minvalue)
Method 2
A(A==0)=nan
[min_value, row_idx]=min(A)
Weitere Antworten (1)
Voss
am 10 Jun. 2022
A(A~=0) is a 4-by-1 vector:
A=[0; 5 ;6 ;9 ;55];
A(A~=0)
When you do min on that you find that 5 is the minimum, which occurs at index 1, as you can see right there.
To get the correct index in A (not in A(A~=0)) of the non-zero minimum, you can store the indices of the non-zero elements of A:
nz_idx = find(A~=0)
then use min:
[min_value,temp_idx] = min(A(nz_idx))
and then get the index in A:
row_idx = nz_idx(temp_idx)
2 Kommentare
Siehe auch
Kategorien
Mehr zu Matrices and Arrays finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!