how to make computations with a cell array?

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simo borto
simo borto am 29 Jan. 2015
Bearbeitet: Michael Haderlein am 29 Jan. 2015
I have a cell array:
results = {5,2};
that is:
results =
[1x5 double] [1x1 prob.NormalDistribution ]
[1x5 double] [1x1 prob.tLocationScaleDistribution]
[1x5 double] [1x1 gmdistribution ]
[1x5 double] [1x1 gmdistribution ]
[1x5 double] [1x1 struct ]
so there is 5 vectors made of 5 doubles (but the number of vectors is not important). Writing something like:
results{3,1}(2) = 3;
there are no problems: the second place of the third vector of the "first column" of the cell array becomes equal to 3.
My purpose is to compute the minimum value of the fifth places of all the vectors (in the first column of the cell array)
I have tried with:
lower = min(results{:,1}(5));
And it gives:
Bad cell reference operation.
I have tried very different ways to obtain something, but always the same error.
Is there a simple solution to my problem? Thank you in advance

Akzeptierte Antwort

Guillaume
Guillaume am 29 Jan. 2015
Bearbeitet: Guillaume am 29 Jan. 2015
Yes, you can't do that. Mostly because
result{:, 1}
expands into a comma separated list which of course can't be indexed.
If all the vectors of column 1 are the same size, then the simplest thing is to convert that cell column into a matrix, and then operate on a matrix:
col1 = cell2mat(results(:, 1));
lower = min(col1(:, 5))
If the vectors are not the same size, cell2mat won't work and you have to use cellfun to extract this fifth element:
lower = min(cellfun(@(v) v(5), results(:, 1)))

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Michael Haderlein
Michael Haderlein am 29 Jan. 2015
Bearbeitet: Michael Haderlein am 29 Jan. 2015
Dear Simo,
min(cellfun(@(x) x(5),results(:,1)))
does the job.
Best regards,
Michael

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