Have latex (bold) and variable in legend of a figure

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Miraboreasu
Miraboreasu am 26 Mai 2022
Kommentiert: Miraboreasu am 27 Mai 2022
Hello,
I have two lines in one figure, one is called error, and the other is typed by latex form as well as the first element of array ```x```, but I tried to use sprintf, but the results are wierd
```
x=[1.1, 2.1, 3.1]
legend( 'Error',sprintf('\bf[$\bf\frac{t v_p}{r_{well}}$] (\bf$\Pi_1$) = %f', x(1)), 'Location','best','Interpreter','latex' )
```
  2 Kommentare
KSSV
KSSV am 26 Mai 2022
What you want to display in legend?
Miraboreasu
Miraboreasu am 26 Mai 2022
Bearbeitet: Miraboreasu am 26 Mai 2022
Hello, you mean what is this latex for?
this, thank you

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Akzeptierte Antwort

KSSV
KSSV am 26 Mai 2022
Bearbeitet: KSSV am 26 Mai 2022
plot(rand(1,10)) ;
hold on
plot(rand(1,10)) ;
legend( 'Error','$[\frac{tv_p}{r_{well}}](\Pi_1=)$','Interpreter','latex', 'Location','best')
set(gca,'FontSize',24)
  3 Kommentare
KSSV
KSSV am 27 Mai 2022
plot(rand(1,10)) ;
hold on
plot(rand(1,10)) ;
legend( '\bf Error','$\bf [\frac{tv_p}{r_{well}}](\Pi_1=)$','Interpreter','latex', 'Location','best')
set(gca,'FontSize',24)
Miraboreasu
Miraboreasu am 27 Mai 2022
Thank you, but how to use the element from my array ```x```

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Weitere Antworten (1)

Sam Chak
Sam Chak am 26 Mai 2022
I think this should work:
legend({'$\left[\frac{t v_{p}}{r_{well}}\right] \left(\Pi_{1}\right)$'}, 'Interpreter', 'latex', 'location', 'best')

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R2021b

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