Ploting some ode's solution.

hello. I want to plot some graph that ode(ordinary differential equation)'s solution(I will make this solution to polynomial from exponential with Taylor Series) . How can I plot that? How can I code it?
y''-5y'+4y = 0

Antworten (1)

Torsten
Torsten am 25 Mai 2022
Bearbeitet: Torsten am 25 Mai 2022

0 Stimmen

The general solution is
y(t) = C1*exp(4*t) + C2*exp(t)
for arbitrary constants C1 and C2.
Look up "dsolve" and the examples provided under

9 Kommentare

Yeachan Choi
Yeachan Choi am 26 Mai 2022
hey, Thx But I should take this solution to polynomial eqn from exp with Taylor series... How can I do that???
Torsten
Torsten am 26 Mai 2022
Not clear. Include your precise assignment question.
Yeachan Choi
Yeachan Choi am 26 Mai 2022
I mean, I will ploting (y''-5y'+4y = 0)'s solution, y(t) = C1*exp(4*t) + C2*exp(t). But I want to make this for polynomial equation. (I will use Taylor Series.)
Torsten
Torsten am 26 Mai 2022
I don't understand
But I want to make this for polynomial equation. (I will use Taylor Series.)
Can you give an example ?
Yeachan Choi
Yeachan Choi am 26 Mai 2022
your solution is exponential function right? But I want to make your solution to be a polynomial function, so I will use Taylor Series in matlab
Torsten
Torsten am 26 Mai 2022
Bearbeitet: Torsten am 26 Mai 2022
So you want to make the ansatz
y(t) = sum_{i=0}^{i=oo} a_i * t^i
and determine the coefficients a_i ?
Yeachan Choi
Yeachan Choi am 26 Mai 2022
I will give C1 C2 and the other coefficients as a randi(). So I need the code for Taylor series.
Torsten
Torsten am 26 Mai 2022
Bearbeitet: Torsten am 26 Mai 2022
I give up.
All solutions to the equation
y''-5y'+4y = 0
are given by
y(t) = C1*exp(4*t) + C2*exp(t)
for constants C1 and C2.
There are no polynomial solutions, except for the case that C1 = C2 = 0.
So I can't understand what you mean "you want to make the solution a polynomial function".
Of course, you can do
syms C1 C2 t
f = C1*exp(4*t) + C2*exp(t);
taylor(f,t,'Order',8)
but why ?
Yeachan Choi
Yeachan Choi am 26 Mai 2022
haha But Thank you.

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