Fit data with a given equation for 3 variables

I want to fit my data to the following equation, but I dont know how to force the program to take the b values which i have, instead of calculating them automatically, I attached here my code which i wrote
fy = @(a,b,x) ((1-(x/a)).^(-a*b));
x = [0,0.1, 0.2, 0.3, 0.4, 0.46, 0.55, 0.6];
y = [0.001, 0.00111499, 0.0011926, 0.0013699, 0.00161633, 0.00192075, 0.00274991, 0.00357156];
b = [0, 1.1499, 0.963, 1.233, 1.540825, 2.001630435, 3.181654545, 4.285933333];
B = fmincon(@(c) norm(y - fy(c(1),c(2),x)), [1; 1], [],[],[],[], [0 0],[1 90]);
fprintf('PhiMax = %.15f\nVisco = %.15f\n', B)
xv = linspace(min(x), max(x));
figure(1)
plot(x, y, 'pg')
hold on
plot(xv, fy(B(1),B(2),xv), '-r')
hold off
grid

2 Kommentare

Torsten
Torsten am 24 Mai 2022
How should it be possible to have the value for b if you don't know the value for a ?
Tesla
Tesla am 24 Mai 2022
Indeed i am looking for the value of a

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 Akzeptierte Antwort

Torsten
Torsten am 24 Mai 2022
Bearbeitet: Torsten am 24 Mai 2022

0 Stimmen

Your function is not suited to reflect your data.
x = [0,0.1, 0.2, 0.3, 0.4, 0.46, 0.55, 0.6];
y = [0.001, 0.00111499, 0.0011926, 0.0013699, 0.00161633, 0.00192075, 0.00274991, 0.00357156];
b = [0, 1.1499, 0.963, 1.233, 1.540825, 2.001630435, 3.181654545, 4.285933333];
p0 = 1;
B = lsqnonlin(@(a)fy(a,x,y,b),p0,max(x),Inf)
fprintf('PhiMax = %.15f\nVisco = %.15f\n', B)
figure(1)
plot(x, y, 'pg')
hold on
plot(x, fy(B(1),x,y,b)+y, '-r')
hold off
grid
function res = fy(a,x,y,b)
res = ((1-(x/a)).^a).^b - y;
end

1 Kommentar

Thanks a lot, it works, I just need to multipy the function by 0.001.
function res = fy(a,x,y,b)
res = 0.001*((1-(x/a)).^a).^b - y;
end

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Weitere Antworten (1)

How about this?
You only need to think about c as follows:
fy = @(a,b,x) ((1-(x/a)).^(-a*b));
x = [0,0.1, 0.2, 0.3, 0.4, 0.46, 0.55, 0.6];
y = [0.001, 0.00111499, 0.0011926, 0.0013699, 0.00161633, 0.00192075, 0.00274991, 0.00357156];
b = [0, 1.1499, 0.963, 1.233, 1.540825, 2.001630435, 3.181654545, 4.285933333];
B = fmincon(@(c) norm(y - fy(c,b,x)),1,[],[],0,1)
Converged to an infeasible point. fmincon stopped because the size of the current step is less than the value of the step size tolerance but constraints are not satisfied to within the value of the constraint tolerance. Consider enabling the interior point method feasibility mode.
B = 6.6511e+03

1 Kommentar

Tesla
Tesla am 24 Mai 2022
Thank you for the suggestion but the fitting plot is not working

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Version

R2021b

Gefragt:

am 24 Mai 2022

Kommentiert:

am 24 Mai 2022

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