How do I count how many times in a row a value occurs?

17 Ansichten (letzte 30 Tage)
David Haydock
David Haydock am 17 Mai 2022
Bearbeitet: Torsten am 17 Mai 2022
If I have some list, say:
A = [1 2 4 3 1 1 1 1];
How do I calculate and store *how many times in a row* each number occurs?
For example, for the value 1, I would want an output of [1, 4], since it appears one time, then when it appears again in the list it repeats four times.
Any help would be appreciated.

Akzeptierte Antwort

Monica Roberts
Monica Roberts am 17 Mai 2022
Probably not the fastest/cleanest but this should work. Assuming that A contains at least one value.
ind = find(A==1);
answer = [];
count = 1;
for i = 1:numel(ind)-1
d = ind(i+1)-ind(i);
if d == 1
count = count+1;
else
answer = [answer,count];
count = 1;
end
end
answer = [answer,count];

Weitere Antworten (1)

Torsten
Torsten am 17 Mai 2022
Bearbeitet: Torsten am 17 Mai 2022
A = [1 2 4 3 1 1 1 1];
Au = unique(A);
count = arrayfun(@(i)numel(find(A==Au(i))),1:numel(Au))
output = [Au;count].'
Your question is unclear since the 1 appears 5 times in the row. If you want the maximum number of subsequent repetitions of a number or something similar, you should again formulate your question properly.

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