optimization of delayed differential equations (dde)

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Malgorzata Wieteska
Malgorzata Wieteska am 9 Mai 2022
Kommentiert: Torsten am 14 Mär. 2024
Hello,
I try to optimise (finding the parameter's value) in the system of dde, unfortunately I can't find any example how to do it. I used to optimization of ode using ode45 solver with lsqlin for instance. I will appreciate the help. The dde23 seems not to be working with lsqlin. I will appreciate any help.
  1 Kommentar
Torsten
Torsten am 9 Mai 2022
Bearbeitet: Torsten am 9 Mai 2022
Do you have a code for your model equations set up with dde23 ?
If yes, you should include it and tell which parameter(s) you are trying to optimize on the basis of which input data.

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Torsten
Torsten am 9 Mai 2022
Bearbeitet: Torsten am 9 Mai 2022
Make the best of it.
pTrue = [1 1 1 1 1 1 1 1 1];
time = 0:7;
Y = ...;
Am1=[1,1.1,1.4,0.7,0.8,1.6,2,1.5];
Bm1=[1.5,1.0,0.4,1.7,0.9,1.3,1.5,1.4];
Am=@(t)interp1(time,Am1,t)
Bm=@(t)interp1(time,Bm1,t)
p = lsqnonlin(@(p) Errors(p,time,Y,Am,Bm),0.8*pTrue)
function res = Errors(p,time,Y,Am,Bm)
lags=[1,2];
[T,SOL]=dde23(@(t,y,Z)ddefunEx(t,y,Z,p,Am,Bm), lags, [1,1,1,1], time);
res = Y-SOL;
res = res(:);
end
function dydt = ddefunEx(t,y,Z,p,Am,Bm)
ylag1 = Z(:,1);
ylag2 = Z(:,2);
E1p=y(1)
E2p=y(2)
A1=y(3)
B1=y(4)
n_A=p(1);%0.6;
n_B=p(2);%0.1;
KE1=p(3);%0.2;
KE2=p(4);%0.2;
Vp_A=p(5);%1.2;
Vp_B=p(6);%1.5;
alpha_p=p(7);%0.4;
kA=p(8);%0.4;
kB=p(9);%1.2;
%Auxiliary equations
ALPHA1=n_A*E1p*A1/(KE1*(1+A1))-A1;
ALPHA2=n_B*E2p*B1/(KE2*(1+B1))-B1;
dydt= [Vp_A*Am(t)-alpha_p*ylag1(1);
Vp_B*Bm(t)-alpha_p*ylag1(2);
kA*Am(t)-ylag2(3)-ALPHA1+ALPHA2;
kB*Bm(t)-ylag2(4)+ALPHA1-ALPHA2];
end
  4 Kommentare
Priya Verma
Priya Verma am 14 Mär. 2024
how to plot graphs between lags and variables for dde ?...please reply ..
Torsten
Torsten am 14 Mär. 2024
What do you mean by your question ? The line
[T,SOL]=dde23(@(t,y,Z)ddefunEx(t,y,Z,p,Am,Bm), lags, [1,1,1,1], time);
gives you a solution SOL at times T that you can plot. How do you think that the lags come into play ?

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Malgorzata Wieteska
Malgorzata Wieteska am 9 Mai 2022
% I'm embedding simplified version of the system. I run it the function ddedunEx to get simulated data (Y) and then try to optimise for the values of the parameters against obtained earlier data.
function dydt = ddefunEx(t,y,Z,p)
%global p
ylag1 = Z(:,1);
ylag2 = Z(:,2);
time=0:7;
E1p=y(1)
E2p=y(2)
A1=y(3)
B1=y(4)
Am1=[1,1.1,1.4,0.7,0.8,1.6,2,1.5];
Bm1=[1.5,1.0,0.4,1.7,0.9,1.3,1.5,1.4];
Am=interp1(time,Am1,t)
Bm=interp1(time,Bm1,t)
n_A=p(1);%0.6;
n_B=p(2);%0.1;
KE1=p(3);%0.2;
KE2=p(4);%0.2;
Vp_A=p(5);%1.2;
Vp_B=p(6);%1.5;
alpha_p=p(7);%0.4;
kA=p(8);%0.4;
kB=p(9);%1.2;
%Auxiliary equations
ALPHA1=n_A*E1p*A1/(KE1*(1+A1))-A1;
ALPHA2=n_B*E2p*B1/(KE2*(1+B1))-B1;
dydt= [Vp_A*Am-alpha_p*ylag1(1);
Vp_B*Bm-alpha_p*ylag1(2);
kA*Am-ylag2(3)-ALPHA1+ALPHA2;
kB*Bm-ylag2(4)+ALPHA1-ALPHA2;];
end
%lags=[1,2];
%tspan=0:7;
%sol = dde23(@ddefunEx, lags, [1,1,1,1], tspan);
%figure(2)
%plot(sol.x,sol.y)
%%%%%%%%%%%%% Obtaining data
%Y=sol.y+0.05*randn(size(sol.x));
function res=Errors(p,Y)
tspan=0:7;;
x0=[4;1];
lags=[1,2];
[T,X]=dde23(@ddefunEx, lags, [1,1,1,1], tspan);
res1=(X(:,1)-Y(:,1));
res2=(X(:,2)-Y(:,2));
res3=(X(:,3)-Y(:,3));
res4=(X(:,4)-Y(:,4));
res=abs(res1)+abs(res2) +abs(res3)+abs(res4);
%pTrue=[0.6;0.1;0.2;0.2];
%[pOpt,resnorm,res,exitflag,~,lambda,J]=...
% lsqnonlin(@(p) Errors(p,Y),0.8*pTrue);
  2 Kommentare
Priya Verma
Priya Verma am 14 Mär. 2024
these command is not running in my matlab...please share all code..
Priya Verma
Priya Verma am 14 Mär. 2024
what are define Am1 and Bm1 ?

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