Unrecognized function or variable 'qdpfun"
1 Ansicht (letzte 30 Tage)
Ältere Kommentare anzeigen
Crizel Joyz Amano
am 1 Mai 2022
Kommentiert: Crizel Joyz Amano
am 2 Mai 2022
% qdP.m: plot of volumetric flow rate vs. dP
clear all;
dP = -18*1.01325e5; dz = 100; rho = 1e3; mu = 1e-3; L = 1500; D = 0.154; rh = 4.57e-5; % data
x0 = [5 0.001]; % initial guess (x(1)=v, x(2)=f)
x = fsolve(@qdpfun,x0,[],dP,dz,rho,mu,L,D,rh);
v = x(1); f = x(2); Q = x(1)*pi*D^2/4; % volumetric flow rate
dPf = 2*f*rho*L*v^2/D; % pressure drop due to friction loss
fprintf('Volumetric flow rate of water = %g m^3/sec\n', Q);
fprintf('Pressure drop due to friction loss = %g kPa\n', dPf/1000);
function fun = qdpfun(x,dP,dz,rho,mu,L,D,rh)
v = x(1); f = x(2); g = 9.8; Nre = D*v*rho/mu; % Reynolds number
fun = [-v^2/2 + g*dz + dP/rho + 2*f*L*v^2/D; 1/sqrt(f) + 1.7372*log(rh/3.7/D + 1.255/Nre/sqrt(f))];
end
If you'll run the code, it shows, Unrecognized function or variable 'qdpfun'. Please help in solving the error in the code above
0 Kommentare
Akzeptierte Antwort
Davide Masiello
am 2 Mai 2022
Below, I show the right way to pass extra parameters to a function.
clear,clc
dP = -18*1.01325e5;
dz = 100;
rho = 1e3;
mu = 1e-3;
L = 1500;
D = 0.154;
rh = 4.57e-5;
x0 = [5 0.001];
x = fsolve(@(x)qdpfun(x,dP,dz,rho,mu,L,D,rh),x0);
v = x(1);
f = x(2);
Q = x(1)*pi*D^2/4; % volumetric flow rate
dPf = 2*f*rho*L*v^2/D; % pressure drop due to friction loss
fprintf('Volumetric flow rate of water = %g m^3/sec\n', Q);
fprintf('Pressure drop due to friction loss = %g kPa\n', dPf/1000);
function fun = qdpfun(x,dP,dz,rho,mu,L,D,rh)
v = x(1); f = x(2); g = 9.8; Nre = D*v*rho/mu; % Reynolds number
fun = [-v^2/2 + g*dz + dP/rho + 2*f*L*v^2/D; 1/sqrt(f) + 1.7372*log(rh/3.7/D + 1.255/Nre/sqrt(f))];
end
3 Kommentare
Weitere Antworten (0)
Siehe auch
Kategorien
Mehr zu MATLAB Mobile Fundamentals finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!