How to get all possible permutations in binary format?
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lilly lord
am 29 Apr. 2022
Kommentiert: lilly lord
am 2 Mai 2022
Hello, I want to get possible permutation of the vector v which actually contains a boolean values. Suppose the first permutation is v=[b2 b3 b1] . So it put the second column first then third column and finally the first colum and convert it into decimals
B=[0,1,0;0,0,1;1,1,0;0,1,1;1,0,1;1,0,0];
b1=B(:,1);
b2=B(:,2);
b3=B(:,3);
v=[b1 b2 b3];
c=perms(v);
final =bi2de(c)
2 Kommentare
Voss
am 29 Apr. 2022
You say v is a vector, but in the code v is a matrix. And it's not clear why in the code you split the columns of matrix B into three separate variables b1, b2, and b3, only to recombine them into matrix v, so that v is the same as B.
B=[0,1,0;0,0,1;1,1,0;0,1,1;1,0,1;1,0,0];
b1=B(:,1);
b2=B(:,2);
b3=B(:,3);
v=[b1 b2 b3];
isequal(B,v)
Can you please clarify what exactly you want to do? You want all permutations of what exactly?
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DGM
am 29 Apr. 2022
Bearbeitet: DGM
am 30 Apr. 2022
I'm not sure, but are you thinking of something like this?
B = [0,1,0;0,0,1;1,1,0;0,1,1;1,0,1;1,0,0];
% all permutations of the columns of B
v = B(:,perms(1:size(B,2)));
v = reshape(v.',3,[]).'
% convert to dec
c = bi2de(v,'left-msb')
3 Kommentare
DGM
am 30 Apr. 2022
If you want to organize the results in something other than one long vector, you can represent the results for each permutation as columns of a numeric array:
B = [0,1,0;0,0,1;1,1,0;0,1,1;1,0,1;1,0,0];
v = B(:,perms(1:size(B,2)));
v = reshape(v.',3,[]).';
c = bi2de(v,'left-msb');
c = reshape(c,size(B,1),[]) % one column for each perm
If you're thinking of making a bunch of dynamically-created variables for each vector, just don't. It would only make things slower and more problematic. For 8 columns, there are only 107520 permutations, so it's still manageable. You may find that the vast majority are nonunique.
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