How to interpolate the given plot?
3 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
JD_PM
am 28 Apr. 2022
Kommentiert: Star Strider
am 28 Apr. 2022
I plot speed vs. width (the first three columns are the velocity components and the last the width, please see first file here https://drive.google.com/drive/folders/1CgeDuCahVZvLXXkNkGWlPg8lSGyurmI3) using the following code
clc
close all
clear all
warning('OFF', 'MATLAB:table:ModifiedAndSavedVarnames')
%step 0
Qi = readmatrix("004timestepN2Void30mm.csv");
[v,w] = size(Qi);
%step 1
fCom_004 = Qi(:,1);
sCom_004 = Qi(:,2);
tCom_004 = Qi(:,3);
width_004 = [0;Qi(:,w)+0.0075];
U_004 = sqrt(fCom_004.^2 + sCom_004.^2 + tCom_004.^2);
refined_U_004 = [0;U_004];
%step 3
figure
plot(width_004,refined_U_004)
legend('0.004 timestep','Location','bestoutside')
xlabel('width [m] | 30mm profile')
ylabel('U magnitude [m/s]')
axis square;
grid on;
You'll see that the peak is far from being smooth. To fix the issue I am trying to use interpolation. To do so I modified step 3
newX = linspace (0, 0.015,3e3);
newY = interp1(width_0002,refined_U_0002,newX);
figure
plot(newX,newY)
legend('0.004 timestep','Location','bestoutside')
xlabel('width [m] | 30mm profile')
ylabel('U magnitude [m/s]')
axis square;
grid on;
But the following error pops up "Sample points must be unique."
I think I know why this is happening.
By default, Matlab seems to only read the first four decimals of a given number. Notice that in the last column many numbers only differ from the fifth number; that's why Matlab sees them as equal.
Assuming that I am right, how to make Matlab read the full given numbers of a file?
Thanks in advance! :)
0 Kommentare
Akzeptierte Antwort
Star Strider
am 28 Apr. 2022
MATLAB reads what it is given.
%step 0
Qi = readmatrix("JD_PM sampleData30mm.csv");
[v,w] = size(Qi);
%step 1
fCom_004 = Qi(:,1);
sCom_004 = Qi(:,2);
tCom_004 = Qi(:,3);
width_004 = [0;Qi(:,w)+0.0075];
U_004 = sqrt(fCom_004.^2 + sCom_004.^2 + tCom_004.^2);
refined_U_004 = [0;U_004];
%step 3
figure
plot(width_004,refined_U_004)
legend('0.004 timestep','Location','bestoutside')
xlabel('width [m] | 30mm profile')
ylabel('U magnitude [m/s]')
axis square;
grid on;
% % You'll see that the peak is far from being smooth. To fix the issue I am trying to use interpolation. To do so I modified step 3
newX = linspace (0, 0.015,3e3);
[width_004,idx] = unique(width_004, 'stable'); % Eliminate Duplicates
newY = interp1(width_004,refined_U_004(idx),newX);
figure
plot(newX,newY)
legend('0.004 timestep','Location','bestoutside')
xlabel('width [m] | 30mm profile')
ylabel('U magnitude [m/s]')
axis square;
grid on;
I tried different interpolation methods ('pchip', 'spline') and do not see a difference.
.
2 Kommentare
Star Strider
am 28 Apr. 2022
My pleasure!
One option is to develop a nonlinear model for that and fit the data to it.
%step 0
Qi = readmatrix('https://www.mathworks.com/matlabcentral/answers/uploaded_files/982200/JD_PM%20sampleData30mm.csv');
[v,w] = size(Qi);
%step 1
fCom_004 = Qi(:,1);
sCom_004 = Qi(:,2);
tCom_004 = Qi(:,3);
width_004 = [0;Qi(:,w)+0.0075];
U_004 = sqrt(fCom_004.^2 + sCom_004.^2 + tCom_004.^2);
refined_U_004 = [0;U_004];
%step 3
figure
plot(width_004,refined_U_004)
legend('0.004 timestep','Location','bestoutside')
xlabel('width [m] | 30mm profile')
ylabel('U magnitude [m/s]')
axis square;
grid on;
% % You'll see that the peak is far from being smooth. To fix the issue I am trying to use interpolation. To do so I modified step 3
newX = linspace (0, 0.015,3e3);
[width_004,idx] = unique(width_004, 'stable'); % Eliminate Duplicates
newY = sgolayfilt(refined_U_004(idx), 3, 81); % Use 'sgolayfilt'
figure
plot(width_004,newY)
legend('0.004 timestep','Location','bestoutside')
xlabel('width [m] | 30mm profile')
ylabel('U magnitude [m/s]')
axis square;
grid on;
Change the ‘framelen’ value to get the desired result.
The smoothdata function has an ‘sgolay’ option, however I do not know if that requires the Signal Processing Toolbox as well.
.
Weitere Antworten (0)
Siehe auch
Kategorien
Mehr zu Data Preprocessing finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!