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help I have 40 iteration , 10 iteration of 40 at random to do something and the other 30 iteration for do another thing??

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help I have 40 iteration , 10 iteration of 40 at random to do something and the other 30 iteration for do another thing?? for t=1:40 take 10 of 40 at random to do something and other 30 for do another thing

Akzeptierte Antwort

Star Strider
Star Strider am 19 Jan. 2015
If you want to choose 10 iterations randomly out of a total of 40, this is one way:
ran10 = randperm(40, 10); % Choose 10 Random Iterations From 40
for k1 = 1:40
if any(ran10 == k1)
fprintf('\n\tDo something randomly at k1 = %d\n', k1)
else
fprintf('\n\tDo something else at k1 = %d\n', k1)
end
end
  2 Kommentare
maha ismail
maha ismail am 19 Jan. 2015
this is what I need but rewrite this code in a simple code because I work In matlab version 6.5 year2000
Star Strider
Star Strider am 19 Jan. 2015
I don’t know what 6.5 had, but I assume the problem is with randperm.
This restatement of ran10 should work:
ran10 = fix(40*rand(10,1));
(If this solves your problem, please Accept my Answer.)

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Weitere Antworten (1)

Marcel
Marcel am 19 Jan. 2015
Don't quite understand the question. Can't you just create 2 loops?
For i=1:30
<stuff happens>
end
For i=31:40
<other stuff happens>
end
  2 Kommentare
maha ismail
maha ismail am 19 Jan. 2015
I mean the I is not in sequence 10 iteration but not in order may 1 6 8 11 30 25 13 7 5 22 this 10 iteration in random but the other 30 its the other numbers don't selected in the 10 iteration
Stephen23
Stephen23 am 19 Jan. 2015
@ Marcel: you should avoid using i or j as the loop variables, as these are the names of the inbuilt imaginary unit .

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