Filter löschen
Filter löschen

sub2ind is not giving me diesired results

1 Ansicht (letzte 30 Tage)
Lora
Lora am 19 Jan. 2015
Kommentiert: Lora am 19 Jan. 2015
Hi how can you find linear indices of a certain rectangular region in an image. I have its x,y width and height i also have image width and height. Sub2ind is not working or perhaps i dont know how to achieve it using sub2ind. I only want linear indices of a 23x51 area. My X cordinat is 237 and Y is 228 and image size is 375,500. So if provide something like this
linearInd = sub2ind([23 51], 237, 228);
obviously it prompts error that out of range subscript
Thanks

Akzeptierte Antwort

Guillaume
Guillaume am 19 Jan. 2015
Bearbeitet: Guillaume am 19 Jan. 2015
The first argument to sub2ind is the size of your whole image, not the region you want to extract. The second and third arguments would be the coordinates of the image you want to convert to indices. One way to do what you want:
img = randi([0 255], 512, 512); %random 256x256 image for demo
x = 237, y = 228, width = 51, height = 23;
[xx, yy] = meshgrid(x:x+width-1, y:y+height-1);
indices = sub2ind(size(img), yy, xx);
I have to ask, though, why do you want to convert to linear indices?
  1 Kommentar
Lora
Lora am 19 Jan. 2015
It workss thanks. The reason why i am trying to extract is that have ground truth objects in linear indices nd it would be easier to compute overlap.

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (1)

Azzi Abdelmalek
Azzi Abdelmalek am 19 Jan. 2015
Bearbeitet: Azzi Abdelmalek am 19 Jan. 2015
You have a problem with the size of your matrix, if your matrix is 23x51 how can you get the coordinates [237 228]?
  1 Kommentar
Lora
Lora am 19 Jan. 2015
Bearbeitet: Lora am 19 Jan. 2015
yes I know but my question is how can i get linear indices of a just a rectangular region of an image of size(375,500) now the size of my rectangular region is 23x51? but my rectangular region start from (237,228)

Melden Sie sich an, um zu kommentieren.

Kategorien

Mehr zu Images finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by