I'm trying to shade the region over which the integral extends with vertical lines. This is my integral:
F = @(x,y) x.*y;
ymin = @(x) x.^2;
ymax = @(x) x;
q = integral2(F,0,1,ymin,ymax)
The code below produces a graph with vertical line shading over its region. This is an example of what i'm trying to do.
f = @(x) sin(x + 1); g = @(x) x.^3 - 3*x + 1;
fplot(f, [-3, 3]), hold on
fplot(g, [-3, 3], 'LineWidth', 2)
>> x1 = fzero(@(x) f(x) - g(x), -2);
x2 = fzero(@(x) f(x) - g(x), 0);
x3 = fzero(@(x) f(x) - g(x), 2);
>> xcoord = linspace(x1, x3, 10);
ycoord = [f(xcoord); g(xcoord)];
plot([xcoord;xcoord], ycoord), hold off

5 Kommentare

Your code already works. What exactly is your issue?
(note that this code could be optimized to use a single line object, instead of having a separate object of every vertical line, but that doesn't affect the fundamental operation)
f = @(x) sin(x + 1); g = @(x) x.^3 - 3*x + 1;
fplot(f, [-3, 3]), hold on
fplot(g, [-3, 3], 'LineWidth', 2)
x1 = fzero(@(x) f(x) - g(x), -2);
x2 = fzero(@(x) f(x) - g(x), 0);
x3 = fzero(@(x) f(x) - g(x), 2);
xcoord = linspace(x1, x3, 100);
ycoord = [f(xcoord); g(xcoord)];
plot([xcoord;xcoord], ycoord,'k'), hold off
DGM
DGM am 25 Apr. 2022
I'm pretty sure the second code block is an example of what OP wants to apply to the first code block.
Rik
Rik am 25 Apr. 2022
The problem with the first block is that F is not a function of x, but of x and y, so the shading of the second block doesn't make sense, unless the function is converted to a function of x alone.
@Ikenna Iwudike Do you mean you want some sort of surface plot? The shading might be difficult to see.
Ikenna Iwudike
Ikenna Iwudike am 25 Apr. 2022
Yea, let me see how a surface plot would look. Also yes I was talking about the first block.
Rik
Rik am 25 Apr. 2022
See if my edited answer works for you. The loop can be optimized to plot all stems as a single object, but I first wanted to create it like this.

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Rik
Rik am 25 Apr. 2022
Bearbeitet: Rik am 25 Apr. 2022

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I have put some inefficient code at the start to integrate over y so you end up with a function of x alone. I then used the same g function as you used in your second block. Is this what you mean?
F = @(x,y) x.*y;
ymin = @(x) x.^2;
ymax = @(x) x;
f_base =@(x) integral(@(y) F(x,y),ymin(x),ymax(x));
f=@(x) arrayfun(f_base,x);
g = @(x) x.^3 - 3*x + 1;
fplot(f, [-2, 2]), hold on
fplot(g, [-2, 2], 'LineWidth', 2)
x1 = fzero(@(x) f(x) - g(x), -2);
x2 = fzero(@(x) f(x) - g(x), 0);
x3 = fzero(@(x) f(x) - g(x), 2);
xcoord = linspace(x1, x3, 100);
ycoord = [f(xcoord); g(xcoord)];
plot([xcoord;xcoord], ycoord,'k'), hold off
If you want to plot a surface, you can use surf. plot3 will allow you to plot a line in a 3D axes.
F = @(x,y) x.*y;
ymin = @(x) x.^2;
ymax = @(x) x;
[X,Y]=ndgrid(linspace(0,1,100));
Y(Y<ymin(X))=NaN;
Y(Y>ymax(X))=NaN;
Z=F(X,Y);
surf(X,Y,Z)
Az=-5;El=65;view(Az,El) % set azimuth and elevation
hold on
for n=1:numel(Z)
if isnan(Z(n)),continue,end
plot3(X(n)*[1 1],Y(n)*[1 1],[0 Z(n)],'k')
end

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