How can I plot this figure?
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X=[1,2,3,4,5,6,7,8,9,10]
Y=['d=1','d=3','d=2','d=2','d=3','d=1','d=2','d=2','d=1','d=3']
The outcome will be similar to this figure.
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Image Analyst
am 11 Apr. 2022
Bearbeitet: Image Analyst
am 11 Apr. 2022
How are you determining the width of the gray and black strips? Then are you just using repmat() to replicate some row vector vertically to get your vertically striped image?
X=[1,2,3,4,5,6,7,8,9,10]; %days
Y1=[1,0,0,0,1,0,0,0,1,0]; %d=1 (worker 1)
Y2=[0,0,1,1,0,0,1,1,0,0]; %d=2 (worker 2)
Y3=[0,1,0,0,0,1,0,0,0,1]; %d=3 (worker 3)
y2image = uint8(repmat(128*Y2, [15, 1]));
imshow(y2image)
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Voss
am 16 Apr. 2022
You could use create patch objects instead of rectangle objects, and then make a legend from (some of) those patches.
Or you can create patch objects with NaN data (so they don't appear in the axes) in addition to the rectangle objects you already have, one patch for each color, just to be used for the legend:
Face(1).Colours=[0 0 0]; Face(2).Colours=[0.8500 0.3250 0.0980]; Face(3).Colours=[0.9290 0.6940 0.1250];
Y1=[1,0,0,0,1,0,0,0,1,0]; %d=1 (worker 1)
Y2=[0,0,1,1,0,0,1,1,0,0]; %d=2 (worker 2)
Y3=[0,1,0,0,0,1,0,0,0,1]; %d=3 (worker 3)
Days=10;
i=1;
while i<=Days
if Y1(i)==1
rectangle('Position',[(i-0.5) 0 1 1],'FaceColor',Face(1).Colours,'EdgeColor',Face(1).Colours,'LineWidth',0.5)
% axis([0 Days 0 1]);
elseif Y2(i)==1
rectangle('Position',[(i-0.5) 0 1 1],'FaceColor',Face(2).Colours,'EdgeColor',Face(2).Colours,'LineWidth',0.5)
% axis([0 Days 0 1]);
elseif Y3(i)==1
rectangle('Position',[(i-0.5) 0 1 1],'FaceColor',Face(3).Colours,'EdgeColor',Face(3).Colours,'LineWidth',0.5)
% axis([0 Days 0 1]);
end
i=i+1;
end
% (just set the axes limits once, and include the +/- 0.5)
axis([0.5 Days+0.5 0 1]);
% create three patches with NaN data, to be used for making the legend:
p = [patch(NaN,NaN,Face(1).Colours); patch(NaN,NaN,Face(2).Colours); patch(NaN,NaN,Face(3).Colours)];
% make a legend for those three patches
legend(p,{'Y1' 'Y2' 'Y3'}) % (call them what you like)
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