Nonscalar arrays of function handles are not allowed; use cell arrays instead.

syms o p

fun1=o+p;

fun2=o*p+5;

eq1=matlabFunction(fun1);

eq2=matlabFunction(fun2);

bbb=fsolve(@(o,p) [eq1;eq2],[0,1]);

What am I doing wrong?

Answer 1

[Steven Lord]

You need to evaluate the function handles in your fsolve call. Alternately you could skip converting the symbolic expressions into function handles and use solve.

syms o p
fun1=o+p;
fun2=o*p+5;
eq1=matlabFunction(fun1);
eq2=matlabFunction(fun2);
bbb=fsolve(@(op) [eq1(op(1), op(2));eq2(op(1), op(2))],[0,1]) % or

Equation solved.

fsolve completed because the vector of function values is near zero
as measured by the value of the function tolerance, and
the problem appears regular as measured by the gradient.

bbb = 1×2

-2.2361 2.2361

bbb2 = solve(eq1, eq2, o, p)

bbb2 = struct with fields:
    o: [2×1 sym]
    p: [2×1 sym]

vpa(bbb2.o, 5)

ans = 

vpa(bbb2.p, 5)

ans = 

Answer 2

[David Hill]

Why use symbolic and convert?

fun=@(x)[x(1)+x(2);x(1)*x(2)+5];
x=fsolve(fun,[0,1]);

[Tevel Hedi]

i need it to be symbolic in my main code where i use a script of that sort.

Answer 3

[Torsten]

syms o p
fun1 = o+p;
fun2 = o*p+5;
fun = [fun1,fun2];
eq = matlabFunction(fun);
bbb = fsolve(@(x)eq(x(1),x(2)),[0,1]);