ind() function or find() function not working

At first this section of code was working, and return the right indexes, but now its not working. It should be returning: ind = 3 4 but it returns ind = 1

A = [1 1 2 2 3 4 5 6 7 8 9];

a = length(A);

b = A(3)

ind = find(b)

if length(ind) == 1

bmatch = 0

elseif length(ind) > 1

bmatch = 1

else

end

It returns:

b =

2

ind =

1

bmatch =

0

Any help is greatly appreciated!

[Stephen23]

"ind() function or find() function not working"

FIND is working correctly.

You use indexing to select one element of A. Then you use FIND on that one nonzero element which correctly returns the linear index 1. Then because the index is scalar the IF evaluates, giving BMATCH == 0.

So far you have not explained why you think the code should do anything other than what it is doing.

"It should be returning: ind = 3 4 "

Nope, not that code.

[Katherine Sadler]

Oh I thought the FIND would return the index spot of 3 and 4. Thanks

[Stephen23]

All FIND knows about is the scalar input that you have provided it. FIND cannot guess that that scalar array was origianally in position 3 of a larger array, nor can it guess that there were other identical values in that larger array. It only knows about the scalar element that you gave it.

Answer 1

[Dyuman Joshi]

Use

ind = find(A==b);

%find(x) is generally used for matrices to find non-zero values.

[Katherine Sadler]

Thank you that's what I was looking for!