Cummulative sum between NaN values

I have the fllowing Rainfall Data

              NaN
   0.250000000000000
                   0
                   0
   0.250000000000000
                   0
                   0
                   0
   0.250000000000000
                   0
   0.250000000000000
                   0
                   0
   0.250000000000000
                 NaN
   0.250000000000000
                   0
                   0
                   0
   0.250000000000000
   0.250000000000000
                 NaN
   0.250000000000000
   0.760000000000000
     

I would like to find the cummulative Sum between the NaN. It should be:

         NaN
   0.250000000000000
   0.250000000000000
   0.250000000000000
   0.500000000000000
   0.500000000000000
   0.500000000000000
   0.500000000000000
   0.750000000000000
   0.750000000000000
   1.000000000000000
   1.000000000000000
   1.000000000000000
   1.250000000000000
                 NaN
   0.250000000000000
   0.250000000000000
   0.250000000000000
   0.250000000000000
   0.500000000000000
   0.500000000000000
                 NaN
   0.250000000000000
   0.910000000000000

Answer 1

[Chunru]

The result you gave above seems not correct.

 x=[            NaN
   0.250000000000000
                   0
                   0
   0.250000000000000
                   0
                   0
                   0
   0.250000000000000
                   0
   0.250000000000000
                   0
                   0
   0.250000000000000
                 NaN
   0.250000000000000
                   0
                   0
                   0
   0.250000000000000
   0.250000000000000
                 NaN
   0.250000000000000
   0.760000000000000];
 
 idx = find(isnan(x));
 y = x;
 idx = [0; idx; length(x)+1];
 for i=1:length(idx)-1
     y(idx(i)+1:idx(i+1)-1) = cumsum(x(idx(i)+1:idx(i+1)-1));
 end
 
 disp(y)

       NaN
    0.2500
    0.2500
    0.2500
    0.5000
    0.5000
    0.5000
    0.5000
    0.7500
    0.7500
    1.0000
    1.0000
    1.0000
    1.2500
       NaN
    0.2500
    0.2500
    0.2500
    0.2500
    0.5000
    0.7500
       NaN
    0.2500
    1.0100

[Queena Edwards]

Thank You!!!