# Storing information from a loop over 3 variables

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RP am 4 Apr. 2022
Bearbeitet: Geoff Hayes am 4 Apr. 2022
The code below seems to store the results from each loop as opposed to providing the results from the current loop.
So, for example Table(1,1,2) has the results of Table (1,1,1) and Table (1,1,2).
SCR=prctile(x,0.5);
rho=0;
muinputs=[-0.025,-0.010,0.0181,0.025];
sigmainputs=[0.0125,0.0287,0.0501,0.0751];
Table=cell(4,4,9);
for i=1:4
for j=1:4
for ii=1:9
muy=-muinputs(i)*SCR;
sigmay=-sigmainputs(j)*SCR;
%muy=-0.1*SCR;
%sigmay=-0.1*SCR;
y(:,ii)=Testlooping(x,rho,muy,sigmay);
y2(:,ii)=x+y(:,ii);
y3(:,ii)=prctile(y2(:,ii),0.5);
Table{i,j,ii}=y3;
end
end
end
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### Akzeptierte Antwort

Geoff Hayes am 4 Apr. 2022
@RP - look closely at this code
for i=1:4
for j=1:4
for ii=1:9
muy=-muinputs(i)*SCR;
sigmay=-sigmainputs(j)*SCR;
y(:,ii)=Testlooping(x,rho,muy,sigmay);
y2(:,ii)=x+y(:,ii);
y3(:,ii)=prctile(y2(:,ii),0.5);
Table{i,j,ii}=y3;
end
end
end
when ii is 1, then the code is doing
y(:,1)=Testlooping(x,rho,muy,sigmay);
y2(:,1)=x+y(:,1);
y3(:,1)=prctile(y2(:,1),0.5);
Table{i,j,1}=y3;
On the subsequent iteration, when ii is 2, then
y(:,2)=Testlooping(x,rho,muy,sigmay);
y2(:,2)=x+y(:,2);
y3(:,2)=prctile(y2(:,2),0.5);
Table{i,j,2}=y3;
Note that the assignment to Table{i,j,2} is y3 which combines the results of the current iteration and that of the previous. I don't think that you need to maintain this data on each iteration and so the code could be simplified to
y = Testlooping(x,rho,muy,sigmay);
y2 = x + y;
y3 = prctile(y2,0.5);
Table{i,j,2} = y3;
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