How can I plot the contour of the imaginary unit of this function phiz?
9 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
[x,y] = meshgrid(linspace(-4,4));
y = y.*1i;
for k = 1:8
z = x + 1i.*y;
phiz = z + z.^(-1) - 1i.*(k/(2*pi)).*log(z);
figure (4);
contour(x,y,imag(phiz),'-k');
end
0 Kommentare
Antworten (1)
Chandra
am 6 Apr. 2022
Hi,
Imaginary term generally indicates the axis of a graph, (2,3) can be written as 2+3i is some applications and magnitude gives the distance from origin, so if we want to see the imaginary term directly provide the real values in y axis
y = real(y);
%or we can provide magnitude
y = abs(y);
try different values to y and see the contour plot changes.
0 Kommentare
Siehe auch
Kategorien
Mehr zu Contour Plots finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!