symbolic matrix help converting

2 Ansichten (letzte 30 Tage)
grace lim
grace lim am 22 Mär. 2022
Beantwortet: Star Strider am 22 Mär. 2022
syms j w C R h11 h12 h21 h22
%matrix i would like to solve ABCD=[1 (1/(j*w*C))+R; 0 1]
%formular to converting ABCD to h para
A=((h11*h22)-(h12*h21))/h21
B=-h11/h21
C=-h22/h21
D=-1/h21
ABCD=[A B;C D]
i have problem trying to get a matrix from the original matrix(ABCD=[1 (1/(j*w*C))+R; 0 1])
using the formular
A=((h11*h22)-(h12*h21))/h21
B=-h11/h21
C=-h22/h21
D=-1/h21
please help

Antworten (1)

Star Strider
Star Strider am 22 Mär. 2022
One problem is that ‘C’ is being used to designate the capacitor, and also the ‘ABCD’ (2,1) element. Designating the capacitor as ‘Cc’ removes that ambiguity —
syms w Cc R h11 h12 h21 h22
%matrix i would like to solve ABCD=[1 (1/(j*w*Cc))+R; 0 1]
%formular to converting ABCD to h para
A=((h11*h22)-(h12*h21))/h21
A = 
B=-h11/h21
B = 
C=-h22/h21
C = 
D=-1/h21
D = 
ABCD=[A B;C D]
ABCD = 
ABCD = simplify(ABCD, 500)
ABCD = 
S = ABCD == [1 (1/(1j*w*Cc))+R; 0 1]
S = 
[h11 h12 h21 h22] = solve(S,[h11 h12 h21 h22])
h11 = 
h12 = 
h21 = 
h22 = 
0
I also removed ‘j’ and replaced it with the imaginary operator ‘1j’ (that now appears as i) for clarity.
.

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by