Why am i getting length(x) as 11 instead of 16?

n=0:15;

[Walter Roberson]

x and x1 are not the same

Answer 1

[Torsten]

If you display

length(x1)

the answer should be 16.

Answer 2

[Image Analyst]

What did you define for x? All we see are definitions for n and x1:

n=0:15;
% Compute x1
x1 = 1 .* (n >= 1) & (n <= 10)

x1 = 1×16 logical array
   0   1   1   1   1   1   1   1   1   1   1   0   0   0   0   0

x1Length = length(x1) % Display it's length.

x1Length = 16

% Now define some x - a different variable than x1
x = [1,2,3,4] % Or whatever it might be.

x = 1×4

1 2 3 4

xLength = length(x) % Display it's length.

xLength = 4

I bet you had an x hanging around from a prior run and didn't call "clear all" so when you did length(x) you were getting some x that was still in the base workspace even though it was not in your script. Calling clear all would clear all old variables and prevent a problem like that.