Transform table to another format

1 Ansicht (letzte 30 Tage)
Monkey Coder
Monkey Coder am 8 Mär. 2022
Bearbeitet: Monkey Coder am 9 Mär. 2022
I have correlation data in the following format:
Headers Fund1 Fund2 Fund3
_______ _____ _____ _____
"Fund1" 1 0.3 0.5
"Fund2" 0.1 1 0.6
"Fund3" 0.2 0.4 1
Headers = ["Fund1";"Fund2";"Fund3"];
Fund1 = [1;0.1;0.2];
Fund2 = [0.3;1;0.4];
Fund3 = [0.5;0.6;1];
correlData = table(Headers, Fund1, Fund2, Fund3)
How can I transform it to the below format?
Fund_ID1 Fund_ID2 Correlation
________ ________ __________
1 1 1
1 2 0.3
1 3 0.5
2 1 0.1
2 2 1
2 3 0.6
3 1 0.5
3 2 0.6
3 3 1

Akzeptierte Antwort

Simon Chan
Simon Chan am 8 Mär. 2022
Use function stack is another option.
clear;clc;
Headers = ["Fund1";"Fund2";"Fund3"];
Fund1 = [1;0.1;0.2];
Fund2 = [0.3;1;0.4];
Fund3 = [0.5;0.6;1];
correlData = table(Headers, Fund1, Fund2, Fund3);
S = stack(correlData,2:4,'NewDataVariableName','Correlation','IndexVariableName','Fund_ID2')
S = 9×3 table
Headers Fund_ID2 Correlation _______ ________ ___________ "Fund1" Fund1 1 "Fund1" Fund2 0.3 "Fund1" Fund3 0.5 "Fund2" Fund1 0.1 "Fund2" Fund2 1 "Fund2" Fund3 0.6 "Fund3" Fund1 0.2 "Fund3" Fund2 0.4 "Fund3" Fund3 1
S.Properties.VariableNames{1}='Fund_ID1';
S.Fund_ID1 = arrayfun(@(x) sscanf(x,'Fund%d'),S.Fund_ID1);
S.Fund_ID2 = arrayfun(@(x) sscanf(x,'Fund%d'),string(S.Fund_ID2))
S = 9×3 table
Fund_ID1 Fund_ID2 Correlation ________ ________ ___________ 1 1 1 1 2 0.3 1 3 0.5 2 1 0.1 2 2 1 2 3 0.6 3 1 0.2 3 2 0.4 3 3 1
  2 Kommentare
Peter Perkins
Peter Perkins am 9 Mär. 2022
It might even be usefl to start from here:
>> correlData.Headers = categorical(correlData.Headers)
correlData =
3×4 table
Headers Fund1 Fund2 Fund3
_______ _____ _____ _____
Fund1 1 0.3 0.5
Fund2 0.1 1 0.6
Fund3 0.2 0.4 1
and stick with with categoricals, not numbers:
> stack(correlData,2:4,'NewDataVariableName','Correlation','IndexVariableName','Fund_ID2')
ans =
9×3 table
Headers Fund_ID2 Correlation
_______ ________ ___________
Fund1 Fund1 1
Fund1 Fund2 0.3
Fund1 Fund3 0.5
Fund2 Fund1 0.1
Fund2 Fund2 1
Fund2 Fund3 0.6
Fund3 Fund1 0.2
Fund3 Fund2 0.4
Fund3 Fund3 1
Monkey Coder
Monkey Coder am 9 Mär. 2022
Bearbeitet: Monkey Coder am 9 Mär. 2022
Ok, thanks Peter.

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (1)

Arif Hoq
Arif Hoq am 8 Mär. 2022
Bearbeitet: Arif Hoq am 8 Mär. 2022
Headers = ["Fund1";"Fund2";"Fund3"];
Fund1 = [1;0.1;0.2];
Fund2 = [0.3;1;0.4];
Fund3 = [0.5;0.6;1];
correlData = table(Headers, Fund1, Fund2, Fund3)
correlData = 3×4 table
Headers Fund1 Fund2 Fund3 _______ _____ _____ _____ "Fund1" 1 0.3 0.5 "Fund2" 0.1 1 0.6 "Fund3" 0.2 0.4 1
A=table2array(correlData);
B=A(1:2,2:end)';
Correlation=[str2double(B(:)); str2double(A(:,4))];
Fund_ID1=[1 1 1 2 2 2 3 3 3]';
Fund_ID2=[1 2 3 1 2 3 1 2 3]';
Table2=table(Fund_ID1,Fund_ID2,Correlation)
Table2 = 9×3 table
Fund_ID1 Fund_ID2 Correlation ________ ________ ___________ 1 1 1 1 2 0.3 1 3 0.5 2 1 0.1 2 2 1 2 3 0.6 3 1 0.5 3 2 0.6 3 3 1
  1 Kommentar
Monkey Coder
Monkey Coder am 8 Mär. 2022
Thanks Arif Hoq.
Fund_ID1=[1 1 1 2 2 2 3 3 3]';
Fund_ID2=[1 2 3 1 2 3 1 2 3]';
Is there a way to read from correlData table instead of passing the Fund_ID1 and Fund_ID2 again?

Melden Sie sich an, um zu kommentieren.

Produkte


Version

R2018a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by