How do I use the besselj function?
15 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
Nathan Falkner
am 6 Mär. 2022
Beantwortet: Abolfazl Chaman Motlagh
am 6 Mär. 2022
I've been given a row vector v and column vector z:
v = unique(randi(12, [1,4])-1);
z = linspace(0,10*(1+rand(1)),2e2).';
I'm supposed to produce an array M=Jv(z), where the columns of M(z) correspond to each value of v.
This is what I've made so far:
for i = [1:length(v)]
M(i)=besselj(v(i),z(i))
end
I had thought I made a correct array of M, with it being a 1x4 function, like v. However this doesn't allow me to make M a function of z, and I have a feeling I've completely misunderstood the documentation of the besselj function altogether.
0 Kommentare
Akzeptierte Antwort
Abolfazl Chaman Motlagh
am 6 Mär. 2022
The function besselj(nu,x) is in fact two variable function
as
. you put v(i) and z(i) simultaneously with same index in argument of it. means M(i) is
which make it one dimensional array. you should consider some v as you already created and a linespace for spatial variable.
v = unique(randi(12, [1,4])-1);
z = linspace(0,10*(1+rand(1)),2e2).';
for i = 1:numel(v)
M(i,:)=besselj(v(i),z);
end
plot(z,M,'LineWidth',2);grid on;
legend(['J_{' num2str(v(1)) '}'],['J_{' num2str(v(2)) '}'],['J_{' num2str(v(3)) '}'],['J_{' num2str(v(4)) '}'])
if size of v be less than 4 the line legends leads to an array.
0 Kommentare
Weitere Antworten (0)
Siehe auch
Kategorien
Mehr zu Startup and Shutdown finden Sie in Help Center und File Exchange
Produkte
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
