How to specify max. number of outliers on which to apply the Hampel filter?

2 Ansichten (letzte 30 Tage)
I have a timeseries with outliers. However, sometimes these occur consequtively, e.g. 20 datapoints one after the other. This poses a problem when applying Hampel on the entire dataset because it alters data that is actually valid.
I would like to apply the Hampel filter only when there are max. 3 outliers in a Hampel window. How can I do that?
The outliers are values within the vector X that exceed a threshold of abs(X) = 10.
Is there a way to create a new vector which keeps datapoints exceeding 10 if most of the sorrounding datapoints are below 10, and if in a window of 20 values, more than 3 of them exceed the threshold, then those extremes should be replaced with 'NaN'?
Thank you in advance!

Akzeptierte Antwort

Scott MacKenzie
Scott MacKenzie am 5 Mär. 2022
There's probably a simpler way to do this, but I believe the code below achieves what you are after:
% test data
x1 = randi([5 12],1,50);
% filtered data in x2
x2 = x1;
% parameters (adjust as necessary)
ws = 6; % window size
t = 10; % threshold
n = 3; % number of points above threshold (must be >n)
for i=ws:length(x1)
idx1 = i-ws+1;
idx2 = i;
idx = (idx1-1) + find(x1(idx1:idx2) > t );
if length(idx)>n
x2(idx) = nan;
end
end
[x1; x2]
ans = 2×50
7 7 7 7 11 9 10 11 10 5 11 10 12 11 9 12 11 11 8 8 5 11 5 10 7 9 5 6 9 6 7 7 7 7 11 9 10 11 10 5 NaN 10 NaN NaN 9 NaN NaN NaN 8 8 5 11 5 10 7 9 5 6 9 6
  2 Kommentare
Lu Da Silva
Lu Da Silva am 5 Mär. 2022
Bearbeitet: Lu Da Silva am 5 Mär. 2022
The only correction I made is applying the absolute value:
idx = (idx1-1) + find(abs(x1(idx1:idx2)) > t );
Works wonders, thank you!!

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (0)

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by