Error: a singular Jacobian encountered When I use bvp4c
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This is my first time using bvp4c.
I don't know why but when I run the code below, I get error message that a singular Jacobian encountered.
It is strange because first time I run the code with
C1 = 2.6247e+16;
C2 = 1.6201e+15;
C3 = 3.7795e+17;
though I got a warning, it worked. Then I found a mistake and changed these constants to correct ones. And the error appeared.
Could you help me to find my mistake?
% ****************************my code**************************** %
function fcn
clear
n1 = 0;
n2 = 1;
C1 = 2.6247e-2;
C2 = 1.6201;
C3 = 3.7795e+2;
a = 0;
b = 10;
step = 0.01;
solinit = bvpinit(linspace(a,b,10),@schrodINIT);
sol = bvp4c(@schrodODE,@schrodBC,solinit);
z = linspace(a,b,b/step+1);
fint = deval(sol,z);
f = fint(1,:);
plot(z,f,'-');
% *************************** set ODE *************************** %
function dydx=schrodODE(x,y)
if x==0
dydx=[ 0
0 ];
else
X = x*1.0e-8;
dydx=[ y(2)
y(1)*(C1*x^2+C2*(n1+1)+C3/x-(n2/x)^2)-y(2)/x ];
end
end
% **************************** set BC *************************** %
function res=schrodBC(ya,yb)
res=[ ya(1)
ya(2)-1];
end
% ********************* set initial function ******************** %
function yinit=schrodINIT(x)
b1=1.0;
if x==a
yinit=[ 0
1]; % end point B.C.
else
yinit=[ x/exp(b1*x)
b1*(b1*x-2)/exp(b1*x)];
end
end
% *************************************************************** %
end
1 Kommentar
Torsten
am 10 Dez. 2014
Your problem is an IVP, not a BVP (both boundary conditions are given at x=a).
Use an ODE integrator to solve it (e.g. ODE45).
Best wishes
Torsten.
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