how can i plot contour
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khaled Abdelghafar
am 1 Mär. 2022
Kommentiert: Walter Roberson
am 1 Mär. 2022
i encounter an error while trying to plot the following contour
x=0:0.1:4;
x1=-pi:0.001*pi:pi;
y1=(100*sqrt(2*pi)./sqrt(x.*2*pi)).*cos(x1/2).*(1.-sin(x1/2.).*sin(3.*x1/2.));
y2=(100*sqrt(2*pi)./sqrt(x.*2*pi)).*cos(x1/2).*(1.+sin(x1/2.).*sin(3.*x1/2.));
y3=(100*sqrt(2*pi)./sqrt(x.*2*pi)).*cos(x1/2).*sin(x1/2.).*sin(3.*x1/2.);
y4=(1/2).*((y1-y2)^2+y1^2+y2^2+6.*y3^2);
z=abs(sqrt(y4));
[x,x1]=meshgrid(x,x1);
% contour(x,x1,z)
contour(real(z))
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Akzeptierte Antwort
Walter Roberson
am 1 Mär. 2022
x = (0:0.1:4).';
x1=-pi:0.001*pi:pi;
y1=(100*sqrt(2*pi)./sqrt(x.*2*pi)).*cos(x1/2).*(1.-sin(x1/2.).*sin(3.*x1/2.));
y2=(100*sqrt(2*pi)./sqrt(x.*2*pi)).*cos(x1/2).*(1.+sin(x1/2.).*sin(3.*x1/2.));
y3=(100*sqrt(2*pi)./sqrt(x.*2*pi)).*cos(x1/2).*sin(x1/2.).*sin(3.*x1/2.);
y4 = (1/2).*((y1-y2).^2+y1.^2+y2.^2+6.*y3);
z = sqrt(y4);
[x,y]=meshgrid(x1,x);
% contour(x,x1,z)
contour(x, y, real(z))
5 Kommentare
Walter Roberson
am 1 Mär. 2022
You do not need to construct x2 and x3 for that contribution.
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