Root LP problem is unbounded.

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KRISHNA TEJA DUDE
KRISHNA TEJA DUDE am 1 Mär. 2022
p = optimproblem;
x = optimvar('x', 2,'Type','integer','LowerBound',0,'UpperBound',Inf);
p.ObjectiveSense = 'maximize';
p.Objective = 10*x(1) + 20*x(2);
cons1 = 6*x(1) + 8*x(2) >= 48;
cons2 = x(1) + 3*x(2) >=12;
p.Constraints.cons1 = cons1;
p.Constraints.cons2 = cons2;
sol = solve(p);
sol.x
Output ----
Solving problem using intlinprog.
Root LP problem is unbounded.
Intlinprog stopped because the root LP problem is unbounded.
ans =
[]

Akzeptierte Antwort

Torsten
Torsten am 1 Mär. 2022
Yes, I can see it with my naked eye that you can make the objective function as big as you like.
Take x(1) = 1e100, x(2) = 1e100, then x is feasible and the objective gives 30*1e100.

Weitere Antworten (1)

Janardhan Rao Moparthi
Janardhan Rao Moparthi am 28 Dez. 2023
Since you do not specify the boundaries for the variable x(1) and x(2), it is giving error. instead try
  1. if the variables are not binary
lb = zeros(2,1);
ub = [inf;inf];
2.If the variables are binary
lb = zeros(2,1);
ub = [1;1];

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