help solving polynomial equation

5 Ansichten (letzte 30 Tage)
mammad dehghan
mammad dehghan am 28 Feb. 2022
Kommentiert: Torsten am 1 Mär. 2022
clc
clear
syms G J E I l b q Cla ru Ru U w
beta=((E*I)/(G*J));
landa=l/b;
K=((G*J)/l)*[ ((256*beta)/(landa^2)), 0 ((-80*beta)/(landa^2)) , 0;
0, 16/3 , 0 , -8/3;
((-80*beta)/(landa^2)), 0, ((28*beta)/(landa^2)), 0;
0, -8/3, 0, 7/3];
M=2*b^4*l*Ru*[64/105 4/15 -16/105 1/15
4/15 2/15 -1/15 1/60
-16/105 -1/15 4/105 -1/60
1/15 1/60 -1/60 1/30];
A=pi*b*(l/6)*[0 4*b 0 4*b
0 8 0 8
0 b 0 b
0 2 0 2];
B=pi*b*(l/6)*[-4*b 0 -4*b 0
-8 8*b -8 8*b
-b 0 -b 0
-2 2*b -2 2*b];
C=pi*b^2*(l/6)*[0 -b^2/2 0 -b^2/2
-4 0 -4 0
0 -b^2/8 0 -b^2/8
-1 0 -1 0];
Meq=M-ru*C;
Keq=K-ru*U^2*A;
Deq=-ru*U*B;
H=(-w^2)*Meq+(1i*w)*Deq+Keq;
v=det(H)
d=solve(v==0,w)
the above code didnt give the roots of w as function of U, pleas help why ?

Antworten (1)

Torsten
Torsten am 28 Feb. 2022
Bearbeitet: Torsten am 28 Feb. 2022
det(H) is a polynomial of degree 10 in w. Since the roots of polynomials of degree > 4 can't explicitly be given, you will have to use the numerical "roots" or the symbolic "root".
Before, you will have to give numerical values to all other symbolic variables involved.
  2 Kommentare
mammad dehghan
mammad dehghan am 1 Mär. 2022
i can give numerical values to other symbolic variables exept U i want roots in term of U.
Torsten
Torsten am 1 Mär. 2022
Then do after the line v = det(H)
vsubs = subs(v,G,...,J,...,E,...etc);
R = solve(vsubs,U);
Unum = vpa(R )

Melden Sie sich an, um zu kommentieren.

Kategorien

Mehr zu Symbolic Math Toolbox finden Sie in Help Center und File Exchange

Produkte

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by