How to create the random sampling matrix for a certain number of times?

2 Ansichten (letzte 30 Tage)
S Priya
S Priya am 24 Feb. 2022
Bearbeitet: Awais Saeed am 24 Feb. 2022
I need to find random sample(consisting of 40 values) for 16 elements (each different).Using Em22(:,:,i) will help?How to do it?
c=1;
d=20;
y11=c+(d-c)*rand(20,1);
y12=c-(d-c)*rand(20,1);
y=[y11;y12];
Em1=(432*10^6+y*10^6);
for k=1:40
Em11(k)=Em1(k,1); %Elastic Modulus(40 random values)for 1 element
Em22(:,:,i)=Em11(:,:,i); %Elastic Modulus for all elements(Doubt)
end
  2 Kommentare
Arif Hoq
Arif Hoq am 24 Feb. 2022
I am not so much clear about your expectation.just try this
c=1;
d=20;
y11=c+(d-c)*rand(20,1);
y12=c-(d-c)*rand(20,1);
y=[y11;y12];
Em1=(432*10^6+y*10^6);
for k=1:40
Em11(k)=Em1(k,1); %Elastic Modulus(40 random values)for 1 element
Em22(:,k)=Em11(k); %Elastic Modulus for all elements(Doubt)
end
Em22'
S Priya
S Priya am 24 Feb. 2022
Thank you for the answer. Now the values which I am getting for Em22 is for 1 element, I want Em22 matrix (40x1) with 16 elements. (With each Em22 different from one another.)

Melden Sie sich an, um zu kommentieren.

Antworten (1)

Awais Saeed
Awais Saeed am 24 Feb. 2022
Bearbeitet: Awais Saeed am 24 Feb. 2022
What I understood is that you want those 40 values with 16 different c and d, right? If yes, then loop through those values, do your calculations and store it in a multi-dimensional array.
c = [1 2];
d = [20 21];
% loop through c and d
for idx = 1:1:length(c)
y11 = c(idx)+(d(idx)-c(idx))*rand(20,1);
y12 = c(idx)-(d(idx)-c(idx))*rand(20,1);
y = [y11;y12];
Em1 = (432*10^6+y*10^6);
for k=1:40
Em11(k) = Em1(k,1); %Elastic Modulus(40 random values)for 1 element
Em22(:,k,idx) = Em11(k); %Elastic Modulus for all elements(Doubt)
end
end
Em22(:,:,1); % for first element
Em22(:,:,2); % for second element
  2 Kommentare
S Priya
S Priya am 24 Feb. 2022
Bearbeitet: S Priya am 24 Feb. 2022
Thank for the answer but I donot want 40 values with 16 different c and d.
Whatever values I have for Em11(40 random values), those are for 1 element.
I want Em11 matrix for 16 different elements.
Awais Saeed
Awais Saeed am 24 Feb. 2022
You can store Em11 for one element in Em22(:,:,1) and Em11 for another element in Em22(:,:,2) and so on. To access Em22 for first element, just use Em22(:,:,1). I have updated the script for more clarity.

Melden Sie sich an, um zu kommentieren.

Kategorien

Mehr zu Loops and Conditional Statements finden Sie in Help Center und File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by