In a for loop matrix dimension changes?

2 Ansichten (letzte 30 Tage)
Catarina
Catarina am 6 Dez. 2014
Kommentiert: Catarina am 9 Dez. 2014
I'm having a problem. Here is my code:
UFR = 0.042;
alpha = 0.1;
N = 20;
%Wilson function
for p = 1:N
for q = 1:N
W = SWfunction(p,q,alpha,UFR);
end
end
w = inv(W);
for t = 1:s
for h = 1:N
M(:,h) = exp(-(h)*R(t,h));
MU(:,h) = exp(-UFR*h);
Z(:,h) = zeros;
m = transpose(M);
mu = transpose(MU);
z = transpose(Z);
z(:,t) = w.*(m-mu);
end
end
When I run my code matlab tells me matrix dimensions do not agree when calculating z(:,t). But here's what confuses me, when I run the code without that line the matrix dimensions are fine for multiplication (20x20 with 20x1) but when I have that line it changes the variables m and mu to 1x1 matrices... I need z to be a matrix that performs that calculation for all t. Can someone help me?

Akzeptierte Antwort

Roger Stafford
Roger Stafford am 6 Dez. 2014
If 'SWfunction' produces a scalar value, then 'w' will be a scalar, that is 1 x 1, since it is being overwritten 400 times in your first nested loops. That would produce an error at the line
z(:,t) = w.*(m-mu);
You need to use p and q to index 'w' values, as in w(p,q), so as to produce a 20 x 20 matrix.
  3 Kommentare
Roger Stafford
Roger Stafford am 9 Dez. 2014
In the code you show in the above comment the quantity 'w' is still a 1 x 1 scalar. You need W(p,q) instead of W in the line
W = SWfunction(p,q,alpha,UFR);
A second problem is that in the nested for loops that create M and MU you are taking the transpose of arrays that are only partially computed. That makes no sense. You need to be creating the 'm', 'mmu' and 'z' arrays in a later action after M and MU are fully computed.
Also the line
z(:,t) = w(p,q)*mmu(:,t);
makes no sense. The p and q indices have long since become obsolete since they refer to indices in the first set of for loops.
Catarina
Catarina am 9 Dez. 2014
Ok I've figured it out now! Thank you for your help! :)

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (0)

Kategorien

Mehr zu Loops and Conditional Statements finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by